Question
Download Solution PDFIf the system of linear equations
2x + 2y + 3z = a
3x – y + 5z = b
x – 3y + 2z = c
Where a, b, c are non-zero real numbers, has more than one solution, then:Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFIf the system of equations has more than one solution, then D = 0 and D1 = D2 = D3 = 0.
From the given set of equation, we form,
D1 = 0
\(\Rightarrow \left| \begin{matrix} a & 2 & 3 \\ b & -1 & 5 \\ c & -3 & 2 \\ \end{matrix} \right|=0\)
Now,
⇒ a(-2 + 15) – 2(2b – 5c) + 3(-3b + c) = 0
⇒ 13a – 4b + 10c – 9b + 3c = 0
⇒ 13a – 13b + 13c = 0
⇒ a – b + c = 0
∴ b – a – c = 0Last updated on May 23, 2025
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