If two chords AB and CD intersecting at point O and AO = (9x – 2) cm, BO = (2x + 2) cm, CO = 4x cm and DO = (7x – 2) cm, then, find the value of AO (x > 1)?

  1. 12 cm
  2. 14 cm
  3. 16 cm
  4. 18 cm

Answer (Detailed Solution Below)

Option 3 : 16 cm
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Most Asked Topics in UPSC CSE Prelims - Part 1
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Detailed Solution

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We know that,

AO × OB = OC × OD

⇒ (9x – 2) × (2x + 2) = (4x) × (7x – 2)

⇒ 18x2 – 4x + 18x – 4 = 28x2 – 8x

⇒ 10x2 – 22x + 4 = 0

⇒ 10x2 – 20x – 2x + 4 = 0

⇒ 10x(x – 2) – 2(x – 2) = 0

⇒ (x – 2)(10x – 2)  = 0

⇒ x = 2 or x = 0.2

⇒ x = 2

AO = (9x – 2) = (18 – 2) = 16 cm

∴ The value of AO is 16cm.

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