In a PLL-based FM demodulator, the output of the phase detector is proportional to _______.

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  1. the carrier frequency of the FM signal
  2. the amplitude of the FM signal
  3. the frequency deviation of the FM signal
  4. the phase difference between the FM signal and the VCO output

Answer (Detailed Solution Below)

Option 4 : the phase difference between the FM signal and the VCO output
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Detailed Solution

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In a Phase-Locked Loop (PLL)-based FM demodulator, the phase detector is a key component that:

  • Compares the input FM signal with the output of a Voltage-Controlled Oscillator (VCO).

  • Produces an output voltage proportional to the phase difference between the two signals.

How it Works in FM Demodulation:

  1. FM signal → fed into the phase detector.

  2. Phase detector compares it with VCO output.

  3. The output of the phase detector reflects the instantaneous phase difference.

  4. This varying voltage corresponds to the modulating signal (since frequency variations in FM lead to phase changes).

  5. After low-pass filtering, it gives the original message signal.

 Incorrect Options:

Option Why It's Incorrect
1) Carrier frequency The VCO tracks the input frequency; the detector works on phase, not frequency directly.
2) Amplitude PLL FM demodulation is amplitude-insensitive.
3) Frequency deviation While the output of the entire PLL relates to frequency deviation, the phase detector output is directly proportional to phase difference.
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