In a slider-crank mechanism, the velocity of piston becomes maximum when:

Question

Question

This question was previously asked in

HPCL Engineer Mechanical 04 Nov 2022 Official Paper (Shift 2)

Answer 1

Concept:

Single slider crank mechanism:

TOM 3

Velocity of piston is \({v_p} = \omega r\left( {\sin θ + \frac{{\sin 2θ }}{{2n}}} \right)\)

Where r = crank radius, ω = crank speed, n = Obliquity ratio

Velocity of slider will be maximum at θ = 90°, (∵ sin function is maximum at 90° i.e. sin 90° = 1)

∴ Vmax = rω(1 + 0) = rω

When θ = 90°, i.e. crank is perpendicular to the line of stroke, the velocity of the slider is maximum.