In pea, a pure tall plant (TT) is crossed with a short plant (tt). What will be the ratio of pure tall plants to short plants in the F2 generation ?

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CDS 02/2021: GK Previous Paper (Held On 14 Nov 2021)
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  1. 1 : 1
  2. 1 : 3
  3. 3 : 1
  4. 2 : 1

Answer (Detailed Solution Below)

Option 1 : 1 : 1
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The correct answer is 1: 1.

Key Points

  • '​Pure' plants refer to the homozygous condition in plants and 'hybrid' refers to the heterozygous plants.
  • Homozygous - It is the condition in which the pair of alleles determining a phenotype is identical, either both dominant (TT) or both recessive (tt).
  • Heterozygous - It is the condition where 2 different types of alleles are present, one dominant and one recessive (Tt).
  • When a pure tall plant (TT) is crossed with a pure short plant (tt), the F1 generation produces heterozygous tall (Tt) plants.
  • Upon selfing the F1 generation, that is, crossing two heterozygous tall plants, the following numbers of the F2 generation are obtained phenotypically:
    • Three tall plants and one short plant
  • Whereas, genotypically, the following ratio is obtained:
    • One pure tall plant, two heterozygous tall plants, and one pure short plant.
  • Therefore, considering the genotype, the ratio of pure tall plants to pure short plants in the F2 generation is 1:1. Hence, Option 1 is correct.

F3 Madhuri Engineering 25.04.2022 D10

Mistake Points

  • Please note here that the question asks about the ratio of "pure" tall plants to short plants in F2 generation.
  • The usual ratio of 3:1 is for "all" tall plants to short plants.
  • Pure Tall plants : Hybrid Tall plants : Short/Dwarf plants = TT : Tt : tt = 1:2:1
  • Therefore, Pure tall : Pure short = 1:1
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