Question
Download Solution PDFLet working hours in a day be 8 hours. A completes \(\frac{1}{3}\) of a work in 5 days and B, \(\frac{2}{5}\) of the work in 10 days. The number of hours required to do the complete work by both A and B together, is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Working hours in a day = 8 hours
A completes 1/3 of the work in 5 days
B completes 2/5 of the work in 10 days
Formula Used:
Total Work = Time × Efficiency
Calculation:
A completes 1/3 of the work in 5 days.
Total work done by A in 5 × 3 = 15 days
B completes 2/5 of the work in 10 days
Total work done by B in 10 × 5/2 = 25 days
Total work = LCM(15, 25) = 75 units
Efficiency of A = 75/15 = 5
Efficiency of B = 75/25 = 3
Total work done by A and B together = 75/(5 + 3) = 75/8 days
Working hours in a day = 8 hours
Working hours in a 75/8 days = 8 × 75/8 = 75 hours
∴ Option 4 is the correct answer.
Last updated on Apr 21, 2025
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