2 किलोग्रॅम वस्तुमानाची वस्तू 20 मी/से.च्या प्रारंभिक वेगाने वर फेकली जाते. 2 सेकंदांनंतर, तिची गतिज ऊर्जा किती असेल? (g = 10 मी/से2)

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RRB ALP Previous Paper 2 (Held On: 9 Aug 2018 Shift 2)
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  1. 100 J
  2. 0 J
  3. 400 J
  4. 200 J

Answer (Detailed Solution Below)

Option 2 : 0 J
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Key Points

  • गतिज उर्जेची व्याख्या m वस्तुमानाच्या वस्तूला एका बिंदूपासून दुसर्‍या बिंदूकडे निर्दिष्ट वेग v सह हलविण्यासाठी आवश्यक ऊर्जा म्हणून केली जाते.
  • न्यूटनचे गतीचे पहिले समीकरण वापरून,

v = u + at

जिथे v = वस्तूचा अंतिम वेग

  • u = वस्तूचा प्रारंभिक वेग
  • a = वस्तूचे त्वरण
  • t = वस्तूने घेतलेला वेळ

जशी, वस्तू वरच्या दिशेने जात आहे, a = -g, जिथे g = गुरुत्वीय त्वरण

म्हणून, v = u – gt

दिलेले आहे, u = 20 मी/से, t = 2 सेकंद आणि g = 10 मी/से2

वरील सूत्रात ठेवल्यावर, आपल्याला मिळेल,

v = 20 – 10 × 2 = 0

K.E. = ½ mv2  वापरून

जिथे, K.E. = वस्तूची गतिज ऊर्जा

  • m = वस्तूचे वस्तुमान
  • v = वस्तूचा अंतिम वेग

मूल्ये टाकल्यावर, K.E. = ½ × 2 × 0 = 0 J

म्हणून, 2 किलो वस्तुमानाच्या वस्तूची गतिज ऊर्जा शून्य आहे.
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