एक कण विराम अवस्थेपासून सुरू होऊन एका सरळ रेषेत जातो जिच्या गतीचे समीकरण S = 2t3 - t2 - 1 द्वारे दिले जाते. एका सेकंदानंतर कणाचे त्वरण असेल-

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  1. 4 मीटर/सेकंद2
  2. मीटर/सेकंद2
  3. मीटर/सेकंद2
  4. 10 मीटर/सेकंद2

Answer (Detailed Solution Below)

Option 4 : 10 मीटर/सेकंद2
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Detailed Solution

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संकल्पना:

जर s = f(t)

तर, वेळेच्या संदर्भात प्रथम विकलज वेग दर्शवतो

\(v=\frac{ds}{dt}\)

त्वरण याद्वारे दिले जाते

\(a=\left( \frac{{{d}^{2}}S}{d{{t}^{2}}} \right)\)

जेथे s हे विस्थापन आहे

गणना:

दिलेल्याप्रमाणे:

s = 2t3 – t2 - 1 आणि t = 1 सेकंद.

\(\frac{ds}{dt}=6{{t}^{2}}-2t\)

\(\frac{{{d}^{2}}s}{d{{t}^{2}}}=12t-2\)

\({{\left( \frac{{{d}^{2}}s}{d{{t}^{2}}} \right)}_{t=1s}}=12-2=10 \;m/s^2\)

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