Question
Download Solution PDFएक ध्वनी तरंग 339 मीटर प्रति सेकंद-1 वेगाने प्रवास करतो. जर त्याची तरंगलांबी 1.5 सेमी असेल तर तरंगाची वारंवारता किती असेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFयोग्य उत्तर 22600 Hz आहे.
Key Points
- ते दिले:
- आवाजाचा वेग (v) = 339 ms -1
- आवाजाची तरंगलांबी (λ) = 1.5 सेमी
- λ = 0.015 मीटर
- ध्वनीचा वेग(v) = तरंगलांबी (λ) x वारंवारता(f)
- \(f ={v\over{λ}}\)
- \(f ={339\over{0.015}}\)
- वारंवारता = 22600 Hz
Additional Information
- मानवांसाठी श्रवणीय ध्वनीची वारंवारता श्रेणी 20 Hz ते 20,000 Hz दरम्यान असते.
- दिलेल्या ध्वनीची वारंवारता 20,000 Hz पेक्षा जास्त असल्याने तो ऐकू येत नाही.
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