जर \(\frac{(15)^3+(4)^3}{(15^2+4^2-k)}=19\) असेल, तर K चे मूल्य काय आहे?

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SSC CHSL Tier-I Exam 2022 Official Paper (Held On: 10 March, 2023 Shift 3)
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  1. -60
  2. 120
  3. 60
  4. -120

Answer (Detailed Solution Below)

Option 3 : 60
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गणना:

\(\frac{(15)^3+(4)^3}{(15^2+4^2-k)}=19\)

\(\frac{3375+64}{(225+16-k)}=19\)

\(\frac{3439}{(241-k)}=19\)

3439 - 19 × 241 = -19 k

3439 - 4579 = -19 k

-1140 = -19k

k = 60 

∴ पर्याय 3 हे योग्य उत्तर आहे.

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