Question
Download Solution PDFP आणि Q अनुक्रमे 15 दिवस आणि 10 दिवसात प्रकल्प पूर्ण करू शकतात. त्यांनी एकत्र काम करायला सुरुवात केली, पण 2 दिवसांनी Q ला निघून जावे लागले आणि P एकट्याने उरलेले काम पूर्ण केले. संपूर्ण काम किती दिवसात पूर्ण झाले?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF(P + Q) चे 1 दिवसाचे कार्य = 1/15 + 1/10
⇒ (2 + 3)/30
⇒ ५/३०
⇒ १/६
P आणि Q ने 2 दिवसात केलेले कार्य = 1/6 x 2
⇒ १/३
उर्वरित काम = 1 - 1/3
⇒ २/३
आता,
1/15 काम P द्वारे 1 दिवसात केले जाते.
तर, 2/3 काम P द्वारे 15 x 2/3 = 10 दिवसांत केले जाईल
तर, एकूण वेळ = 10 + 2 घेतला जातो
⇒ १२ दिवस
∴ संपूर्ण काम 12 दिवसात पूर्ण झाले.
पर्यायी पद्धत गणना:
15, 10 चा LCM 30 आहे
P = 30/15 = 2 ची कार्यक्षमता
Q = 30/10 = 3 ची कार्यक्षमता
कामाचे दोन दिवस (2 + 3) x 2 = 10 असतील
उर्वरित काम = 30 - 10 = 20
Q बाकी राहिलेले काम P = 20/2 = 10 दिवसांनी केले जाईल
एकूण काम 10 + 2 = 12 दिवसांत झाले
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