राम त्याच्या पैशांपैकी 12 \(\frac{1}{2}\) % गमावतो आणि उर्वरित 75% खर्च केल्यानंतर, 630 रुपये रामाकडे सुरुवातीला किती पैसे होते?

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  1. 2,080 रुपये
  2. 2,880 रुपये
  3. 2,205 रुपये
  4. 2,808 रुपये

Answer (Detailed Solution Below)

Option 2 : 2,880 रुपये
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दिलेल्याप्रमाणे:

राम 12 \(\frac{1}{2}\) % गमावतो आणि उर्वरित 75% खर्च केल्यानंतर, त्याच्याकडे 630 रुपये आहे.

गणना:

रामकडे सुरुवातीला 100a रुपये आहेत असे समजा

100a × 12 \(\frac{1}{2}\) %

⇒ १२ \(\frac{1}{2}\) a

तर,

उर्वरित पैसे = 100a - 12.5a

⇒ 87.5a रुपये

87.5a × 25/100 =  630 रुपये

87.5a = 630 × 4

87.5a = 2520

⇒ a = 2520/87.5

⇒ a = 28.8

तर, 100a = 2880

∴ योग्य उत्तर 2880 रुपये आहे. 

Shortcut Trick 

आपल्याला माहित आहे की, 12 \(\frac{1}{2}\) % = 1/8 आणि 75% = 3/4,

  खर्च करण्यापूर्वी पैसे बाकी
12 नंतर \(\frac{1}{2}\) % तोटा 8 7
खर्च केल्यानंतर 75% 4 1
अंतिम 32 7

तर, 7 युनिट → 630, 

नंतर, 32 युनिट → 630/7 × 32 = 2880 रुपये

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