One of the vertices of a square is the origin and the adjacent sides of the square are coincident with the negative x-axis. If a side is 3 then which pair will not be its vertex.

  1. (-3, 0) & (-3, 3)
  2. (-3, 0) & (0, 3)
  3. (0, -3) & (3, 0)
  4. (-3, 0) & (0, -3)

Answer (Detailed Solution Below)

Option 3 : (0, -3) & (3, 0)
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Detailed Solution

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Concept:

The coordinate axis divides the plane into four equal parts.

F1 Sachin KM Sunny 11.10.21 D1

1. First Quadrant: (+, +)

2. Second Quadrant: (-, +)

3. Third Quadrant: (-, -)

4. Fourth Quadrant: (+, -)

Calculation:

According to the question, the side of the square is 3 units. Therefore,

There are two possible squares with one of the adjacent sides along the negative x-axis

F1 Sachin KM Sunny 11.10.21 D2

Clearly, we can see that, possible coordinates of square are

Case 1: (0, 0), (-3, 0), (-3, 3) & (0, 3)

Case 1: (0, 0), (-3, 0), (-3, -3) & (0, -3)

Hence, coordinates (0, -3) & (3, 0) are not possible because point (3, 0) belongs to positive x-axis.

Hence, option 3 is correct.

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