Question
Download Solution PDFPower available due to an undisturbed wind of speed 10 m/s acting on a turbine rotor of diameter 10 m is 500 kW. What would be the power for a wind speed of 20 m/s?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The power available in the wind is given by the formula:
P α v3
Using the proportionality:
\(({P_1\over P_2})=({v_1\over v_2})^3\)
Calculation
Given, P1 = 500 kW at v1 = 10 m/s
The power P2 at v2 = 20 m/s is calculated as:
\(({500\over P_2})=({10\over 20})^3\)
P2 = 500 × 8
P2 = 4000 kW
Last updated on May 29, 2025
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