Question
Download Solution PDFRefractive indices of glass and water with respect to air are 1.54 and 1.33 respectively, Polarizing angle for a beam entering from glass to water is
This question was previously asked in
RSMSSB Lab Assistant 2016 Official Paper
Answer (Detailed Solution Below)
Option 2 : tan-1 (1.33/1.54)
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RSMSSB Lab Assistant (Science) Paper I: Full Test (Latest Pattern)
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Detailed Solution
Download Solution PDFConcept:
- The angle of incidence at which a beam of unpolarized light falling on a transparent surface is reflected as a beam of completely plane polarised light is called polarising or Brewster angle. It is denoted by ip.
- Brewster's law: It states that when a ray is passed through some transparent medium having refractive index μ at any particular angle of incidence, the reflected ray is completely polarized; and the angle between reflected and refracted ray is 900.
μ = tan θB = tan ipdd = \(\frac{\mu_1}{\mu_2}\)
Where μ = refractive index and θB is Brewster's angle or polarizing angle (ip).
Application:
We have,
μ2 = 1.54
μ1 = 1.33
Hence,
tan θB = 1.33/1.54 = 1.15
Now, θB = tan-1 (1.33/1.54)
Last updated on May 5, 2025
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