Refractive indices of glass and water with respect to air are 1.54 and 1.33 respectively, Polarizing angle for a beam entering from glass to water is

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  1. tan-1 (1.54/1.33)
  2. tan-1 (1.33/1.54)
  3. tan-1 {(1.54 - 1)/(1.33 - 1)}
  4. tan-1 {(1.54 + 1)/(1.33 + 1)}

Answer (Detailed Solution Below)

Option 2 : tan-1 (1.33/1.54)
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Detailed Solution

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Concept:

  • The angle of incidence at which a beam of unpolarized light falling on a transparent surface is reflected as a beam of completely plane polarised light is called polarising or Brewster angle. It is denoted by ip.
  • Brewster's law: It states that when a ray is passed through some transparent medium having refractive index μ at any particular angle of incidence, the reflected ray is completely polarized; and the angle between reflected and refracted ray is 900.

 

F2 J.K 19.5.20 Pallavi D5

μ = tan θB = tan ipdd = \(\frac{\mu_1}{\mu_2}\)

Where μ = refractive index and θB is Brewster's angle or polarizing angle (ip).

Application:

We have,

μ= 1.54

μ1 = 1.33

Hence,

tan θB = 1.33/1.54 = 1.15

Now, θB = tan-1 (1.33/1.54)

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