The condition for power transmission by flow through a pipeline to be maximum is that the loss of head of the flow due to friction throughout the pipeline length is:

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ESE Mechanical 2016 Paper 1: Official Paper
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  1. One-third of the total head at inlet end 
  2. One-fourth of the total head at inlet end 
  3. Three-fourth of the total head at inlet end
  4. One-half of the total head at inlet end 

Answer (Detailed Solution Below)

Option 1 : One-third of the total head at inlet end 
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Detailed Solution

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Net available head (h) at the outlet of the pipe is given by:

h = H - hf

Where,

H is the total head at the inlet and hf be the head loss in the transmission.

\(\rm{h = H - \frac{{4fl{V^2}}}{{2gd}}}\)

Power available at the pipe outlet is given by:

\(\rm{P = w\times Q\times h = w\times\frac{\pi }{4}\times{d^2}\times V\left[ {H - \frac{{4fl{V^2}}}{{2gd}}} \right]}\)

For maximum power

\(\rm{\frac{dP}{{dV}} = 0\; \\\to \;H = 3{h_f}}\)

∴ hf = H/3.

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