The flywheel of a steam engine has a radius of gryation of 1 m and mass of 2500 kg. The starting torque of the steam engine is 1500 Nm and may be assumed constant. The angular acceleration of the flywheel is _______.

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JKSSB JE Mechanical 02 Nov 2021 Shift 1 Official Paper

Answer 1

Concept:

The torque is given by the relation

T = Iα

where 'I' is the moment of inertia and 'α' is the angular acceleration in rad\s2.

Also, I = mk2

where 'm' is the mass and 'k' is the radius of gyration.

∴ T = mk2α

Calculation:

Given:

m = 2500 kg, k = 1 m, T = 1500 Nm

T = mk2α

∴ 1500 = 2500 × 12 × α

α = 0.6 rad/s2