Question
Download Solution PDFThe HCF of \(\frac{1}{2},\frac{3}{4},\frac{5}{6}\) and \(\frac{7}{8}\) is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Four fraction \(\frac{1}{2},\frac{3}{4},\frac{5}{6},\frac{7}{8}\)
Formula used:
H.C.F of fraction \(=\frac{\ H.C.F \ of \ numerator}{\ L.C.M \ of \ denominators}\)
Calculation:
HCF of the fractions
= \(\frac{ \ HCF \ of 1,3,5,7}{\ LCM \ of 2,4,6,8}\)
=\(\frac{1}{24}\)
Hence the correct answer is option(2).
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