Question
Download Solution PDFThe minimum area required for the isolated footing to carry a factored load of 1000 kN constructed over the soil of safe bearing capacity 150 kN/m2 is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Design Load = 1.1 x Unfactored load.
Area required for footing = \(\frac{{{\rm{Design\;axial\;load\;on\;footing\;including\;self\;weight\;of\;footing}}}}{{{\rm{Safe\;bearing\;capacity\;of\;soil\;}}}}\)
Calculation:
Area required for footing = \(\frac{{{\rm{Design\;axial\;load\;on\;footing\;including\;self\;weight\;of\;footing}}}}{{{\rm{Safe\;bearing\;capacity\;of\;soil\;}}}}\)
UnFactored load, P = 1000/1.5 = 666.67 kN
For safe , self-weight is considered as 10 % of load
Adding 10 % of load as self weight = 0.1 ×666.66= 66.66kN
Design load = 666.66 + 66.66 = 733.32 kN
Safe bearing capacity of Soil, q = 150 kN/m2
Area required = \(\frac{{733.32}}{{150}}\) = 4.88 ≈ 4.9 m2Last updated on Mar 27, 2025
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