Question
Download Solution PDFComprehension
Directions: Study the following information carefully and answer the questions.
The given table DI shows the total number of passengers (male and female) who travelled in trains A and B, as well as the number of passengers who travelled in train A.
| Days | Total number of passengers who travelled in trains A and B together | Out of the total number of passengers, the fraction of passengers who travelled by train A |
| Monday | 165 | 7/11 |
| Tuesday | 135 | 2/5 |
| Wednesday | 180 | 8/15 |
| Thursday | 144 | 3/8 |
The number of passengers who travelled in train C on Monday is 8/5th of the number of passengers who travelled in train B on Monday. Find the ratio of the number of passengers who travelled in train C on Monday to the number of passengers who travelled in train B on Wednesday.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGeneral Solution:
| Day | Total Passengers | Fraction in Train A | Passengers in Train A | Passengers in Train B |
|---|---|---|---|---|
| Monday | 165 | 7/11 | 165 × 7 ÷ 11 = 105 | 165 - 105 = 60 |
| Tuesday | 135 | 2/5 | 135 × 2 ÷ 5 = 54 | 135 - 54 = 81 |
| Wednesday | 180 | 8/15 | 180 × 8 ÷ 15 = 96 | 180 - 96 = 84 |
| Thursday | 144 | 3/8 | 144 × 3 ÷ 8 = 54 | 144 - 54 = 90 |
Calculations:
Passengers in Train B on Monday = 60 (from general solution)
Passengers in Train B on Wednesday = 84 (from general solution)
Train C (Monday): 8/5 × 60 = (8 × 60) ÷ 5 = 480 ÷ 5 = 96
Required Ratio:
Train C (Monday) : Train B (Wednesday) = 96 : 84
Simplify: Divide both by 12 → 96 ÷ 12 = 8, 84 ÷ 12 = 7
Thus, the correct answer is 8:7.
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