The principal value of sin−1\(\frac{1}{\sqrt{2}}\) is equal to which of the following?

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. \(\frac{\pi}{4}\)
  2. \(\frac{3\pi}{4}\)
  3. \(\frac{5\pi}{4}\)
  4. none of these

Answer (Detailed Solution Below)

Option 1 : \(\frac{\pi}{4}\)
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Bihar STET Paper 1 Mathematics Full Test 1
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Detailed Solution

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Calculations:

sin(2nπ +- π/4) = 1/√2 

Hence,  sin−1\(\frac{1}{√{2}}\) = sin-1(sin(2nπ +- π/4)) = 1/√2

But the principle value of sin-1 lies from (-π π)

Hence, The Principle value of  sin−1\(\frac{1}{\sqrt{2}}\) = π/4

Hence, The Correct Answer is option 1 .

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