If tan A = \(\frac{7}{24}\), find the value of sin A + cos A.

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. \(\frac{31}{25}\)
  2. \(\frac{25}{31}\)
  3. \(\frac{7}{25}\)
  4. \(\frac{24}{25}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{31}{25}\)
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Bihar STET Paper 1 Mathematics Full Test 1
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Detailed Solution

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Calculations:

Given that tan A = 7/24, this means that:

Opposite (sin A) / Adjacent (cos A) = 7/24

By Pythagorous Theorem

Hypotenuse = √((Opposite side)2 + (Adjacent side)2)

Hypotenuse = √((7)2 + (24)2)

Hypotenuse = √(49 + 576)

Hypotenuse = √(625)

Hypotenuse = 25

So, now we have a right-angled triangle with sides 7 (opposite), 24 (adjacent), and 25 (hypotenuse).

sin A = Opposite/Hypotenuse = 7/25

cos A = Adjacent/Hypotenuse = 24/25

Then, sin A + cos A = 7/25 + 24/25 = 31/25

So, the value of sin A + cos A is 31/25.

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