The radius of gyration about the polar axis of a circular lamina of radius 0.2 m is:

This question was previously asked in
RRB JE ME 22 Apr 2025 Shift 2 CBT 2 Official Paper
View all RRB JE Papers >
  1. 4.1 cm
  2. 0.14 m
  3. 0.1 m
  4. π cm

Answer (Detailed Solution Below)

Option 2 : 0.14 m
Free
General Science for All Railway Exams Mock Test
20 Qs. 20 Marks 15 Mins

Detailed Solution

Download Solution PDF

Concept:

The radius of gyration about the polar axis is given by:

For a circular lamina:

  • Polar moment of inertia,
  • Area,

Calculation:

 

Latest RRB JE Updates

Last updated on Jun 7, 2025

-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.

-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025

-> RRB JE CBT 2 admit card 2025 has been released. 

-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.

-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode. 

-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.

-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research). 

-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.

-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.

-> Attempt RRB JE Free Current Affairs Mock Test here

-> Enhance your preparation with the RRB JE Previous Year Papers

More Moment of Inertia and Centroid Questions

Hot Links: teen patti rules teen patti club teen patti baaz teen patti master 2025 teen patti online