The reaction of MoCl₂ with [Et₄N]CI in dil. HCl and EtOH produce a dianionic hexanuclear metal cluster.

A. The cluster is [Mo₆Cl₁₄]^2-.

B. The cluster has 136 valence electrons.

C. Each metal center has 4 metal-metal bonds.

Identify the correct statement (s) about the cluster.

Concept:-

• The reaction of MoCl2 with [Et4N]CI in dil. HCl and EtOH produce a dianionic hexanuclear metal cluster.

6 MoCl2 + 12 [Et4N]Cl + 4 HCl + 3 EtOH → [Mo6Cl14]2- + 12 [Et4N]+ + 4 H2O + 3 EtCl

Explanation:-

Statement A: The cluster is [Mo6Cl14]2-

• The reaction of MoCl2 with [Et4N]CI in dil. HCl and EtOH produce a dianionic hexanuclear metal cluster.

6 MoCl₂ + 12 [Et₄N]Cl + 4 HCl + 3 EtOH → [Mo₆Cl₁₄]^2- + 12 [Et₄N]⁺ + 4 H₂O + 3 EtCl

• In this reaction, MoCl₂ reacts with [Et₄N]Cl in the presence of dilute HCl and EtOH to produce a dianionic hexanuclear metal cluster ([Mo₆Cl₁₄]^2-) along with tetraethylammonium cations ([Et₄N]⁺), water (H₂O), and ethyl chloride (EtCl) as byproducts.
• Thus, statement A is correct.

Statement B: The cluster has 136 valence electrons.

• Total number of valence electrons for the cluster [Mo6Cl14]2- ​is

[Mo6Cl14]2- = 4 of the 6 Cl bridge to other Mo₆ clusters + For each Mo₆: 8 Cl capping faces 4 (½ Cl) bridging 2 Cl unique 12 Cl / Mo₆ cluster.

= 136 electrons

Statement C: Each metal center has 4 metal-metal bonds.

• In the cluster [Mo6Cl14]2-, each metal center has 4 M-M bonds.
• Thus, statement C is correct.

Conclusion:-

• Hence, the correct statement (s) about the cluster A, B, and C.