Question
Download Solution PDFThe value of Planck's constant is _________ × 10-34 Js.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Planck’s constant: It is a physical constant that is the quantum of electromagnetic action. It relates the energy carried by a photon to its frequency by, E = hν.
\(\therefore h=\frac{E}{\nu }\)
Hence, the unit of Planck's constant is
\(h=\frac{Joule}{1/sec}=Joule\cdot sec\)
The unit of Planck's constant is Joule⋅sec and it value is 6.6 × 10-34 Js.
Where,
E = energy,
ν = frequency
h = Planck’s constant.
Explanation:
From the above explanation, we can see that, Planck's constant is a fundament constant used to define quantum energy.
And its value is approximately 6.6 × 10-34 Js.
Hence option 3 is correct among all
Last updated on Apr 16, 2025
-> RVUNL JE Result 2025 out! Candidates can check their result on official website @rrvunl.exam.in.
-> Candidates who have cleared cut off will be called for Document Verification.
-> RVUNL JEN Exam was conducted on 11th and 12th April 2025 for Junior Engineer and Junior Chemist posts.
-> The RVUNL JEN Notification 2025 was released for 228 vacancies.
-> The application process was started on 30th January 2025 and ended on 20th February 2025.
-> Engineering graduates, between 21 to 43 years of age can apply for the RVUNL JE Recruitment.
-> The selection process includes a written test and document verification.