The variation of electric field with respect to distance from centre of a charged conducting spherical shell of radius R is given by :

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CUET Physics 18th Aug 2022 Official Paper
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  1. F1 Madhuri UG Entrance 19.04.2023 D13
  2. F1 Madhuri UG Entrance 19.04.2023 D14
  3. F1 Madhuri UG Entrance 19.04.2023 D15
  4. F1 Madhuri UG Entrance 19.04.2023 D16

Answer (Detailed Solution Below)

Option 2 : F1 Madhuri UG Entrance 19.04.2023 D14
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Detailed Solution

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Concept:

  • For a conducting spherical shell of radius R that carries a charge Q, the electric field inside the shell is zero.
  • And outside the shell, the electric field behaves as if all the charge Q is concentrated at the center of the shell.
  • Thus, the electric field outside the shell, at a distance r from the center, is given by Coulomb's law:

E = kQ/r2

where k is the Coulomb constant.

Therefore, the electric field outside the shell varies inversely with the square of the distance from the center of the shell.

That is, as the distance from the center of the shell increases, the electric field strength decreases rapidly.

So, the plot of electric field w.r.t the distance "r" would be,

F1 Madhuri UG Entrance 19.04.2023 D14

The correct answer is option "2"

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