Question
Download Solution PDFTwo containers X and Y contain a mixture of milk and water. In container X, the ratio of milk to water is 5:2. In container Y, the ratio of milk to water is 3:4. The mixtures from X and Y are mixed together in the ratio 7:5 respectively to form a new mixture. How much milk is present in 84 liters of the new mixture?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Container X has milk : water = 5 : 2
Container Y has milk : water = 3 : 4
Mixtures from X and Y are mixed in the ratio 7 : 5
Total final mixture = 84 liters
Total parts of mixture:
7 parts from X and 5 parts from Y
→ Total = 7 + 5 = 12 parts
So,
Mixture from X = (7/12) × 84 = 49 liters
Mixture from Y = (5/12) × 84 = 35 liters
Milk in each container
Container X:
Ratio 5:2 → Total parts = 7
Milk part = (5/7) × 49 = 35 liters
Container Y:
Ratio 3:4 → Total parts = 7
Milk part = (3/7) × 35 = 15 liters
Total milk in the new mixture:
Milk = 35 + 15 = 50 liters
Thus, the correct answer is 50 litres.
Last updated on Jul 22, 2025
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