Which of the following logical operations could be computed by the given network?

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SSC JE EE Previous Paper 10 (Held on: 10 Dec 2020)
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  1. C = AB
  2. C = A + B
  3. \(C = \overline {AB} \)
  4. \(C = \overline {A + B} \)

Answer (Detailed Solution Below)

Option 2 : C = A + B
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Detailed Solution

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Concept:

In Digital Electronics, Logic 1 means High and Logic 0 means low.

Whenever in diode, if 1 is applied to anode and 0 to cathode then Diode acts as a short circuit i.e. ON.

And if 0 is applied to anode and 1 to cathode Diode acts as open circuit i.e. OFF.

F1 Jai 18.1.21 Pallavi D17

Explanation:

The given logic circuit is

F1 Jai 18.1.21 Pallavi D18

For different logic of A and B,4 cases are there and according to that logic of C will vary.

Case 1

When A is logic 0 and B is logic 0

F1 Jai 18.1.21 Pallavi D19

Then the logic of C will be 0.

Case 2

When A is logic 0 and B is logic 1

F1 Jai 18.1.21 Pallavi D20

Then the logic of C will be 1.

Case 3

When A is logic 1 and B is logic 0

F1 Jai 18.1.21 Pallavi D21

Then the logic of C will be 1.

Case 4

When A is logic 1 and B is logic 1

F1 Jai 18.1.21 Pallavi D22

Then the logic of C will be 1.

According to Result, we make a table

A

B

C

0

0

0

0

1

1

1

0

1

1

1

1

This Table is of Logic OR gate.

C = A + B

Important Points

Logic Circuit for AND gate is C = AB

F1 Jai 18.1.21 Pallavi D23

A

B

C

0

0

0

0

1

0

1

0

0

1

1

1

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