Age MCQ Quiz - Objective Question with Answer for Age - Download Free PDF

Given: 

The ratio of the ages of Preeti & Jyoti, 7 years ago = 7 : 6 

Calculation: 

Let the present ages of Preeti and Jyoti be y years and z years respectively. 

7 years ago, the ratio of ages of Preeti & Jyoti = (y - 7)/(z - 7) = 7/6

⇒ 6y - 42 = 7z - 49 

⇒ 6y - 7z = - 7          (1)

Now by checking with ratios in the options; 

Option 1: 

6 years from now, the ratio of ages of Preeti & Jyoti = (y + 6)/(z + 6) = 15/14 

⇒ 14y + 84 = 15z + 90

⇒ 14y - 15z = 6        (2)

By solving equations (1) and (2), we get z = 67/4 and y = 1029/56

∴ 6 years from now, 15 : 14 can be the ratio of their ages. 

Similarly, in option 3 and 4, y and z have positve values. 

Option 2: 

Ratio of ages 6 years from now = 13: 11

⇒ (y + 6)/(z + 6) = 13/11

⇒ 11y - 13z = 12           (3) 

By solving equation (1) and (3), we get z = -149 and y = - 175

∴  y and z have negative values, 6 years from now the above ratio cannot represent the ages of Preeti & Jyoti. 

Given:

Ratio of Misha's age to Kamal's age (present) = 4 : 3

Ratio of their ages after 9 years = 7 : 6

Calculations:

Let Misha's present age be 4x years.

Let Kamal's present age be 3x years.

After 9 years:

Misha's age will be (4x + 9) years.

Kamal's age will be (3x + 9) years.

According to the given ratio after 9 years:

\(\frac{4x + 9}{3x + 9}\) = \(\frac{7}{6}\)

Cross-multiply the terms:

⇒ 6 × (4x + 9) = 7 × (3x + 9)

⇒ 24x + 54 = 21x + 63

⇒ 24x - 21x = 63 - 54

⇒ 3x = 9

⇒ x = \(\frac{9}{3}\)

⇒ x = 3

Now, calculate their present ages:

Misha's present age = 4x = 4 × 3 = 12 years

Kamal's present age = 3x = 3 × 3 = 9 years

Difference in their present ages = Misha's present age - Kamal's present age

⇒ Difference = 12 - 9

⇒ Difference = 3 years

∴ The difference in their present ages is 3 years.

Given:

The ages of Misha and Kamal are in the ratio 2:3.

After 6 years, the ratio of their ages will be 7:9.

Formula used:

Let the present ages of Misha and Kamal be 2x and 3x respectively.

After 6 years, their ages will be (2x + 6) and (3x + 6).

The given ratio after 6 years is:

\(\dfrac{2x+6}{3x+6} = \dfrac{7}{9}\)

Calculation:

\(\dfrac{2x+6}{3x+6} = \dfrac{7}{9}\)

⇒ 9(2x + 6) = 7(3x + 6)

⇒ 18x + 54 = 21x + 42

⇒ 21x - 18x = 54 - 42

⇒ 3x = 12

⇒ x = 4

Present ages:

Misha's age = 2x = 2 × 4 = 8

Kamal's age = 3x = 3 × 4 = 12

Difference in their ages = 12 - 8 = 4

∴ The correct answer is option (1).

Given:

The ratio of Mona's and Priya's present age is 9 ∶ 10.

After 4 years, the ratio of their ages becomes 11 ∶ 12.

Calculation:

Let Mona's present age be 9x and Priya's present age be 10x.

After 4 years, their ages will be 9x + 4 and 10x + 4 respectively.

According to the given condition:

\(\dfrac{9x + 4}{10x + 4} = \dfrac{11}{12}\)

⇒ 12(9x + 4) = 11(10x + 4)

⇒ 108x + 48 = 110x + 44

⇒ 2x = 4

⇒ x = 2

Mona's present age = 9x = 9 × 2 = 18 years

∴ The correct answer is option 1.

Given:

The average age of three boys is 15 years and their ages are in proportion 3 : 5 : 7.

Formula used:

Average = Total sum of ages / Number of boys

Calculations:

Let the ages of the boys be 3x, 5x, and 7x.

Average age = 15

⇒ (3x + 5x + 7x) / 3 = 15

⇒ 15x / 3 = 15

⇒ 5x = 15

⇒ x = 3

⇒ The age of the youngest boy = 3x = 3 × 3 = 9 years

∴ The correct answer is option 1.

Let my current age = x years and my cousin’s age = y years.

Three-fifths of my current age is the same as five-sixths of that of one of my cousins’,

⇒ 3x/5 = 5y/6

⇒ 18x = 25y

My age ten years ago will be his age four years hence,

⇒ x – 10 = y + 4

⇒ y = x – 14,

⇒ 18x = 25(x – 14)

⇒ 18x = 25x – 350

⇒ 7x = 350

Let Peter and Preeti's age be A and B respectively.

The difference between Peter and Preeti’s ages is 5 years,

⇒ A – B = 5

35 years ago, 4 times Peter’s age was the same as 5 times the age of Preeti’s,

⇒ 4(A – 35) = 5(B – 35)

⇒ 4A – 140 = 5B – 175

⇒ 5B – 4A = 35

Solving,

⇒ 5B – 4(5 + B) = 35

⇒ 5B – 20 – 4B = 35

⇒ B = 55

⇒ A = 60

Given:

A - B = 3, B + C = 78, C + D = 33 and the average age of the family is 34 years

Formula used:

Total age = Average age × total number of peoples

Calculation:​

Total age of the family = 4 × 34 = 136 years

A + B + C + D = 136

⇒ A + B = 136 – 33     (∵ C + D = 33)

A + B = 103 years      ---- (i)

A – B = 3 years (Given)      ----- (ii)

From (i) and (ii)

2A = 106 years

∴ A = 53 years

B = 103 – 53 = 50 years    ( from i )

Also C + B = 78    (Given)

⇒ C = 78 – 50 = 28 years

∴ B – C = 50 – 28 = 22 years

Let the age of Sooraj be x years and of Arjun be y years.

⇒ x = 3y       ----(1)

After 8 years,

⇒ x + 8 = (5/2) (y + 8)      

⇒ 2x + 16 = 5y + 40 

putting the value of x from eq (1)  

⇒ 2 × 3y + 16 = 5y + 40   

⇒ 6y + 16 = 5y + 40

⇒ y = 24      ----(2)

Solving Equation (1) and (2), we get:

⇒ x = 72 and y = 24

 After another 8 years, the age of Sooraj = (72 + 8 + 8) = 88 years

The age of Arjun = (24 + 8 + 8) = 40 years

As per question,

Suraj age / Arjun age = 88/40

⇒ 2 × 8/40

⇒ \(2\frac{1}{5}\)

∴ After another 8 years, Sooraj would be \(2\frac{1}{5}\) times Arjun’s age.

Confusion Points Here in question it is given after 8 years ,that means first from current age we need to add 8 years and after that 8 years from then is added, so total 16 years. 

Krish is 5 years younger than Parthiv,

⇒ K + 5 = P

Eight years ago, three times the age of Krish was 10 more than twice the age of Parthiv,

⇒ 3(K – 8) = 2(P – 8) + 10

⇒ 3K – 24 = 2P – 16 + 10

⇒ 3K – 2P = 18

⇒ 3K – 2(K + 5) = 18

⇒ K = 28

Given:

Ratio of Present age of A and B = 5 : 3

The difference between the age of A 10 years hence and the age of B 4 years ago = 20 years

Calculation:

Let the Present age of A and B be 5x and 3x respectively

⇒ The age of A 10 years hence = 5x + 10 

⇒ The age of B 4 years ago = 3x - 4

Now, the difference:

 (5x + 10) - (3x - 4) = 20

⇒ 2x + 14 = 20

⇒ 2x = 6

⇒ x = 3

∴ The present age of A = 5x = 5 × 3 = 15 years

Given:

Ratio between the Present ages of A & B is 5 : 4

The age of A, 3 years ago is 2 years more than the age of B 4 years hence

Calculation:

Ratio between the Present ages of A & B is 5 : 4

⇒ Ages of A and B can be represented as 5x and 4x respectively

Now, the age of A, 3 years ago is 2 years more than the age of B 4 years hence

(5x - 3) = (4x + 4) + 2

⇒ x = 9

Total age of A and B = 5x + 4x = 9x

∴ Total age = 9 × 9 = 81 years

Let the age of elder cousin be ‘x’ years.

⇒ Age of younger cousin = ‘y’ years

The sum of the present ages of two cousins in 46 years,

⇒ x + y = 46       ----(1)

Eight years ago, the elder one was twice as old as the younger one,

⇒ (x - 8) = 2(y - 8)

⇒ x - 2y = -8       ----(2)

Subtracting equation (1) from equation (2) we set

⇒ y = 18

Let the current age of Shaan be x years and of Uddalak be y years

⇒ Given, x = 1.6y – 4       ----(1)

26 years ago,

⇒ y – 26 = 0.5(x – 26) – 1       ----(2)

Put value of equation (1) in (2)

⇒ y – 26 = 0.5(1.6y – 30) – 1

⇒ y – 26 = 0.8y – 16

⇒ y = 50 years

⇒ x = 76 years

Let ages of Virat and Mohinder be A and B years respectively.

Seven years from now Virat will be twice as old as Mohinder,

⇒ (A + 7) = 2(B + 7)

⇒ A – 2B = 7

Five years ago, Mohinder’s age was one year less than 2/5 of Virat’s age,

⇒ (B – 5) = 2/5(A – 5) – 1

⇒(B - 5) = \(\frac{2A - 10 - 5}{5}\)

⇒ 5B - 25 = 2A - 15

⇒ 2A – 5B = -10

⇒ 2(7 + 2B) – 5B = -10

⇒ B = 24

⇒ A = 7 + 48 = 55