Laws of Motion MCQ Quiz - Objective Question with Answer for Laws of Motion - Download Free PDF

Last updated on May 27, 2025

Latest Laws of Motion MCQ Objective Questions

Laws of Motion Question 1:

Which of the following has the largest inertia ?

  1. A pin
  2. An inkpot
  3. Your physics text book
  4. Your body
  5. None of the above

Answer (Detailed Solution Below)

Option 4 : Your body

Laws of Motion Question 1 Detailed Solution

The correct answer is Your body.

Concept:

Newton’s First Law: It states that a body continues in its state of rest or uniform motion in a straight line until and unless an unbalanced force acts on it.

  • Newton’s First Law is also known as the law of inertia.
  • Inertia is the property of the inability of a body to change its position of rest or uniform motion in a straight line.
  • It is valid only in an inertial frame.
  • Mass is the measure of the inertia of a body.
  • The higher the mass of the body, the higher would be its inertia.

Key Points

  • Hence amongst the following options, the human body has the highest mass thus it has the highest inertia.
  • Inertia is a property of an object to resist changes in its current state of motion and is directly proportional to the mass of the object.
  • Mass is solely dependent upon the inertia of the object.
  • Higher the inertia more mass the body will have and vice versa.
  • A heavier object has a higher tendency to resist changes in its state of motion.

Laws of Motion Question 2:

When a bus starts suddenly, the passengers are pushed back. This is an example of which of the following?

  1. Newton's first law
  2. Newton's second law
  3. Newton's third law
  4. None of Newton's laws

Answer (Detailed Solution Below)

Option 1 : Newton's first law

Laws of Motion Question 2 Detailed Solution

The correct answer is Newton's first law.

CONCEPT:

  • Newton’s first law of motion: It is also called the law of inertia. Inertia is the ability of a body by virtue of which it opposes a change.
  • According to Newton’s first law of motion, an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.
  • The inertia of rest: When a body is in rest, it will remain at rest until we apply an external force to move it. This property is called inertia of rest.
  • The inertia of motion: When a body is in a uniform motion, it will remain in motion until we apply an external force to stop it. This property is called inertia of motion.

EXPLANATION:

  • When a bus suddenly starts moving, the passengers fall backward due to the law of inertia of rest or 1st law of Newton.
  • Because the body was in the state of rest and when the bus suddenly starts moving the lower body tends to be in motion, but the upper body still remains in a state of rest due to which it feels a jerk and falls backward. Hence option 1 is correct.

Additional Information

Laws of Motion given by Newton are as follows:

Law of Motion Statement
First Law of motion  An object continues to remain at rest or in a state of uniform motion along a straight line unless an external unbalanced force acts on it.
The second law of motion The rate of change of momentum is proportional to the applied force and the change of momentum occurs in the direction of the force.
Third law of motion  Every action force has an equal and opposite reaction force which acts simultaneously.

Laws of Motion Question 3:

A block of mass m₁ = 1 kg and another block of mass m₂ = 2 kg are placed together on an inclined plane with angle of inclination θ . Various values of θ are given in Column I. The coefficient of friction between the block m₁ and the plane is always zero. The coefficient of static and dynamic friction between the block m₂ and the plane are equal to μ = 0.3. In Column II, expressions for the friction on block m₂ are given. Match the correct expression of the friction in Column II with the angles given in Column I. The acceleration due to gravity is denoted by g. [Given: tan(5.5°) ≈ 0.1, tan(11.5°) ≈ 0.2, tan(16.5°) ≈ 0.3]

Column I Column II
(P) θ = 5° (1) m₂g sin θ
(Q) θ = 10° (2) (m₁ + m₂)g sin θ
(R) θ = 15° (3) μm₂g cos θ
(S) θ = 20° (4) μ(m₁ + m₂)g cos θ

  1. P → 1, Q → 2, R → 2, S → 3
  2. P → 2, Q → 2, R → 3, S → 3
  3. P → 2, Q → 1, R → 3, S → 1
  4. P → 1, Q → 1, R → 2, S → 2

Answer (Detailed Solution Below)

Option 2 : P → 2, Q → 2, R → 3, S → 3

Laws of Motion Question 3 Detailed Solution

Calculation:

The forces on block m₁ are: its weight m₁g, normal reaction from the inclined plane N₁, and the reaction from block m₂ as R.

The forces on block m₂ are: m₂g, N₂, R, and the frictional force f.

If θ is slowly increased, f starts increasing and reaches its maximum value f = μN₂ at θ = θr (angle of repose).

From Newton’s second law:

f = μN₂

R = m₁g sin θ

N₁ = m₁g cos θ

f = R + m₂g sin θ

N₂ = m₂g cos θ

qImage681d9f91fee88e53e8a763dd

Solving these, we get the angle of repose:

θr = tan−1[(μ × m₂) / (m₁ + m₂)] = tan−1[(0.3 × 2) / (1 + 2)] = tan−1(0.2) = 11.5°

So:

For θ = 5° and θ = 10°, blocks are at rest with frictional force:

f = R + m₂g sin θ = (m₁ + m₂)g sin θ

For θ = 15° and θ = 20°, blocks are moving with frictional force:

f = μN₂ = μm₂g cos θ

Laws of Motion Question 4:

Distance between the centres of two stars is 10a. The masses of the stars are M and 16M and their radii a and 2a respectively. A body of mass m is fired straight from the surface of the larger star towards the surface of the smaller star. Its minimum initial speed to reach the surface of the smaller star is found to be √((αGM) /(9a)). The correct value of α will be   

Answer (Detailed Solution Below) 45

Laws of Motion Question 4 Detailed Solution

Calculation:

Let the gravitational attraction by the two stars be equal and opposite at the point P.

The mass m should be projected with a velocity such that it just reaches P, beyond which it is automatically attracted by the mass M. At point P: 

(G × M × m) / r1² = (G × 16M × m) / r2²

Which gives: r2 = 4r1

Using r1 + r2 = 10a, we get:

r1 = 2a and r2 = 8a

Let vmin be the minimum velocity required for mass m to reach point P.

Using conservation of energy:

(1/2) m vmin² − (16 G M m) / r2 − (G M m) / r1 = 0

Substitute r1 = 2a and r2 = 8a:

⇒ vmin = (3/2) × √(5GM / a) = √((45GM) / (9a))

Laws of Motion Question 5:

Masses M1, M2 and M3 are connected by strings of negligible mass which passes over massless and frictionless pulleys P1 and P2 as shown in figure. The masses move such that the portion of the string between P1 and P2 is parallel to the inclined plane and the portion of the string between P2 and M3 is horizontal. The masses M2 and M3 are 4.0 kg each and the coefficient of kinetic friction between the masses and the surface is 0.25. The inclined plane makes an angle of 37° with the horizontal. If the mass M1 moves downwards with a uniform velocity, the value of M1 is x/10. The value of x is [Take g = 9.8 m/s², sin 37° ≈ 3/5.]

qImage681c87bf9b02e02d1ef80b68

Answer (Detailed Solution Below) 42

Laws of Motion Question 5 Detailed Solution

Calculation:
The masses M1, M2, and M3 are connected by inextensible strings. Since M1 moves downward with uniform velocity, all three masses move with the same velocity. Thus, the net force on each mass is zero.

Let T1 be the tension in the string connecting M1 and M2, and T2 the tension in the string connecting M2 and M3.

Let the normal reactions be N2 and N3 for masses M2 and M3, and the frictional forces be f2 = μN2 and f3 = μN3.

qImage681c87bf9b02e02d1ef80b75

Apply Newton’s second law on each block:

  1. T1 = M1g
  2. N2 = M2g cos 37°
  3. T1 = T2 + μN2 + M2g sin 37°
  4. N3 = M3g
  5. T2 = μN3

Now solve the equations:

From (5): T2 = μM3g = 0.25 × 4 × 9.8 = 9.8 N

Substitute into equation (3):

M1g = T2 + μM2g cos 37° + M2g sin 37°

M1 = [T2 + μM2g cos 37° + M2g sin 37°] / g

= [9.8 + (0.25 × 4 × 9.8 × 4/5) + (4 × 9.8 × 3/5)] / 9.8

= [9.8 + 7.84 + 23.52] / 9.8 = 41.16 / 9.8 ≈ 4.2 kg

Answer: M1 = 21/5 kg = 42/10 kg

Top Laws of Motion MCQ Objective Questions

When a bus starts suddenly, the passengers are pushed back. This is an example of which of the following?

  1. Newton's first law
  2. Newton's second law
  3. Newton's third law
  4. None of Newton's laws

Answer (Detailed Solution Below)

Option 1 : Newton's first law

Laws of Motion Question 6 Detailed Solution

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The correct answer is Newton's first law.

CONCEPT:

  • Newton’s first law of motion: It is also called the law of inertia. Inertia is the ability of a body by virtue of which it opposes a change.
  • According to Newton’s first law of motion, an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.
  • The inertia of rest: When a body is in rest, it will remain at rest until we apply an external force to move it. This property is called inertia of rest.
  • The inertia of motion: When a body is in a uniform motion, it will remain in motion until we apply an external force to stop it. This property is called inertia of motion.

EXPLANATION:

  • When a bus suddenly starts moving, the passengers fall backward due to the law of inertia of rest or 1st law of Newton.
  • Because the body was in the state of rest and when the bus suddenly starts moving the lower body tends to be in motion, but the upper body still remains in a state of rest due to which it feels a jerk and falls backward. Hence option 1 is correct.

Additional Information

Laws of Motion given by Newton are as follows:

Law of Motion Statement
First Law of motion  An object continues to remain at rest or in a state of uniform motion along a straight line unless an external unbalanced force acts on it.
The second law of motion The rate of change of momentum is proportional to the applied force and the change of momentum occurs in the direction of the force.
Third law of motion  Every action force has an equal and opposite reaction force which acts simultaneously.

Due to an acceleration of 2 m/s2, the velocity of a body increases from 20 m/s to 30 m/s in a certain period. Find the displacement (in m) of the body in that period.

  1. 650
  2. 125
  3. 250
  4. 325

Answer (Detailed Solution Below)

Option 2 : 125

Laws of Motion Question 7 Detailed Solution

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CONCEPT:

  • Equation of motion: The mathematical equations used to find the final velocity, displacements, time, etc of a moving object without considering force acting on it are called equations of motion.
  • These equations are only valid when the acceleration of the body is constant and they move on a straight line.
  • There are three equations of motion:

V = u + at

V2 = u2 + 2 a S

\({\text{S}} = {\text{ut}} + \frac{1}{2}{\text{a}}{{\text{t}}^2}\)

Where, V = final velocity, u = initial velocity, s = distance traveled by the body under motion, a = acceleration of body under motion, and t = time taken by the body under motion.

EXPLANATION:

Given - Acceleration (a) = 2 m/s2, Final velocity (v) = 30 m/s and Initial velocity (u) = 20 m/s

Displacement = s

We know,

⇒ v2 - u2 = 2as (Equation of Motion)

⇒ s = (v2- u2)/ (2 x a)

⇒ s = (302-202) / (2 x 2)

⇒ s = 500 /4

⇒ s = 125 m

The work to be done to increase the speed of a 0.5 kg ball from 4 m/s to 8 m/s is:

  1. 8 J
  2. 12 J
  3. 16 J
  4. 4 J

Answer (Detailed Solution Below)

Option 2 : 12 J

Laws of Motion Question 8 Detailed Solution

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CONCEPT:

Work done:

It is the dot product of Force and Displacement.

Work Done (W) = Force (F) × Displacement (S)

Kinetic energy: 

The energy of a particle due to its velocity is called kinetic energy.

It is denoted by K.E.

\(K.E=\frac{1}{2}mV^2\)

where m = mass of the particle and V = velocity of the particle.

Work energy theorem:

The work done by all the forces on a system is equal to change in kinetic energy of the system.

Work done by all the forces (W) = Final K.E – Initial K.E

CALCULATION:

Given that:

Initial velocity (u) = 4 m/s, final velocity (v) = 8 m/s and

Mass (m) = 0.5 kg

Applying the work-energy theorem:

Work done = Change in Kinetic Energy:

ΔK.E = (K.E)2 - (K.E)1

\(\Rightarrow \frac{1}{2}m(v^2-u^2)\)

\(\Rightarrow \frac{1}{2}\times\;0.5\times(8^2-4^2)\)

∴ ΔK.E is 12 J

A ball balanced on a vertical rod is an example of

  1. Stable equilibrium
  2. Unstable equilibrium
  3. Neutral equilibrium
  4. Perfect equilibrium

Answer (Detailed Solution Below)

Option 2 : Unstable equilibrium

Laws of Motion Question 9 Detailed Solution

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CONCEPT

  • Equilibrium: It is a state where resultant of all forces acting on a body is zero.
  • Stable equilibrium: A system is said to be in stable equilibrium if, when displaced from equilibrium, it experiences a net force or torque in a direction opposite the direction of the displacement.
  • The potential energy is minimum in this case.

F1 J.K 12.6.20 Pallavi D6

  • Unstable equilibrium: A system is in unstable equilibrium if, when displaced from equilibrium, it experiences a net force or torque in the same direction as the displacement from equilibrium.
    • The potential energy is maximum in this case.

F1 J.K 12.6.20 Pallavi D7

  • Neutral equilibrium: A system is in neutral equilibrium if its equilibrium is independent of displacements from its original position.
    • The potential energy remains constant in this case.

F1 J.K 12.6.20 Pallavi D8

EXPLANATION

  • If a ball is placed on vertical rod, it is in unstable equilibrium because once it is displaced from its place, it will experience the net force in the direction of displacement and never come back to its original position.
  • The potential energy of the ball is maximum at this point.

 

F1 J.K 12.6.20 Pallavi D9

∴ Option 2 is correct.

A car accelerates uniformly from 18 km/h to 36 km/h in 5 s. what is the acceleration in m/s?

  1. 0.5 m/s2
  2. 3 m/s2
  3. 1 m/s2
  4. 2 m/s2

Answer (Detailed Solution Below)

Option 3 : 1 m/s2

Laws of Motion Question 10 Detailed Solution

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Concept:

Acceleration: 

  • The rate of change of velocity is called the acceleration of the body. i.e.,\(a = \frac{{{v_2} - {v_1}}}{{{t_2} - {t_1}}}\)
  • Where V2 = final velocity of the object, V1 = initial velocity of the object, t2 = final time, and t1 = initial time
  • It is a vector quantity.
  • Its direction is the same as that of change in velocity (Not of the velocity).

Calculation:

Given - u = 18 km/h = 5 m/s v = 36 km/h = 10 m/s and t = 5 s

velocities in m/s would be 

u = 18 × 5/18 = 5 m/s and v = 36 ×5/18 = 10 m/s 

  • As acceleration is written as
  • \(\Rightarrow a = \frac{{{v_2} - {v_1}}}{{{t_2} - {t_1}}} \)
  • \(\Rightarrow a = \frac{{{10} - {5}}}{5}=1m/s^2 \)

Hence the correct answer is 1m/s2

A body of mass 4 kg accelerates from 15 m/s to 25 m/s in 5 seconds due to the application of a force on it. Calculate the magnitude of this force (in N).

  1. 32
  2. 8
  3. 16
  4. 64

Answer (Detailed Solution Below)

Option 2 : 8

Laws of Motion Question 11 Detailed Solution

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CONCEPT:

  • Force: Force is a push or pulls on an object. A force can cause an object to accelerate, slow down, remain in place, or change shape.

Force exerted = mass x acceleration

⇒ F = m × a

Acceleration = (Final velocity - Initial velocity)/time

⇒ a = (v- v1) / t

Where F is the force exerted on the body, m is the mass of the body, a is the acceleration of the body, v2 is the final velocity, v1 is initial velocity and t s time.

Calculation:

Given data:

the mass of the body m = 4 kg, Final velocity v= 25 m/s, Initial velocity v1 = 15 m/s, time t = 5 s.

We know that,

⇒ Acceleration = (Final velocity - Initial velocity)/time

a = (25 - 15)/5 m/s2 = 2 m/s2

Also,

⇒ Force exerted = mass x acceleration

⇒ Force = 4 × 2 = 8 N

  • So option 2 is correct.

An Odometer is an instrument used to measure ________ in automobiles.

  1. Speed
  2. Odour
  3. Direction
  4. Distance

Answer (Detailed Solution Below)

Option 4 : Distance

Laws of Motion Question 12 Detailed Solution

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CONCEPT

  • Odometer or odograph: It is a device used to measure the distance travelled by the vehicle.
  • Speedometer or speed meter: A device used by the vehicle to measure the speed of the vehicle.
  • Compass: A magnetic device used to find direction on the earth.

EXPLANATION

  • As explained above odometer is used to measure the distance in automobiles. Therefore option 4 is correct.

Which of the following is NOT a force?

  1. Tension
  2. Normal
  3. Mass
  4. Weight

Answer (Detailed Solution Below)

Option 3 : Mass

Laws of Motion Question 13 Detailed Solution

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CONCEPT:

  • Force: The interaction which after applying on a body changes or try to change the state of rest or the state of motion is called force.
  • Mass is the amount of matter in any substance. It is not a force.
  • Weight: The gravitational force acting on any object on the earth's surface is called its weight.
  • Tension in a rope: In the ideal case rope is massless and intangible, the force on one side is equal to force on the other side.
  • Normal force: It is a force that is exerted by the surface perpendicular to the body. It is a component of the contact force.

F1 J.S 18.5.20 Pallavi D 1

EXPLANATION

  • Since the mass is the amount of matter in a substance which is not a force. Hence option 3 is correct.

What is the mass of an object that requires a force of 90 N to accelerate at a rate of 2.6 m/s2?

  1. 44.6 kg
  2. 34.6 kg
  3. 54.6 kg
  4. None of these

Answer (Detailed Solution Below)

Option 2 : 34.6 kg

Laws of Motion Question 14 Detailed Solution

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CONCEPT:

  • Force: The interaction which after applying on a body changes or try to change the state of motion or state of rest is called force.
  • Force is denoted by F and the SI unit is Newton (N).

Force (F) = Mass (m) × acceleration (a)

CALCULATION

Given - Force (F) = 90 N and acceleration (a) = 2.6 m/s2

  • The force required to accelerate a body of mass “m” with acceleration “a” is given by:

⇒ F = ma

⇒ 90  = m × 2.6

⇒ m = 90/2.6 

⇒ m  = 34.6 kg

Which one of the following has maximum inertia? 

  1. An atom
  2. A molecule
  3. A one-rupee coin
  4. A cricket ball

Answer (Detailed Solution Below)

Option 4 : A cricket ball

Laws of Motion Question 15 Detailed Solution

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CONCEPT:

  • Newton’s first law of motion: It is also called the law of inertia. Inertia is the ability of a body by virtue of which it opposes a change.
  • According to Newton’s first law of motion, an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.
  • The inertia of rest: When a body is in rest, it will remain at rest until we apply an external force to move it. This property is called inertia of rest.
  • The inertia of motion: When a body is in a uniform motion, it will remain in motion until we apply an external force to stop it. This property is called inertia of motion.

EXPLANATION:

  • The heavier the object is harder to move it or the greater the amount of force required to move it hence higher the inertia.
  • Since higher mass has higher inertia. In all the above 4 options, a cricket ball has maximum mass so it will have maximum inertia. Hence option 4 is correct.
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