Number based MCQ Quiz - Objective Question with Answer for Number based - Download Free PDF

The logic followed here is:

Logic: The fractions simplify to whole numbers.

Let's check each option,

1) 22/5 → Simplify to 4.4 ⇒ Doesn't follow the logic.

2) 16/4 → Simplify to 4

3) 80/20 → Simplify to 4

4) 39/13 → Simplify to 3

Here, we can see that option 1 is different from the others.

Hence, the correct answer is "22/5".

The logic followed here is:

Logic: The numbers are square numbers.

Let's check each option:

1) 125 → 125 is not a square number ⇒ Doesn't follow the logic.

2) 196 → 196 is the square number of 14.

3) 16 → 16 is the square number of 4.

4) 256 → 256 is the square number of 16.

Here, we can see that Option 1 doesn't follow the logic.

Hence, the correct answer is "125".

The logic followed here is:

Logic: 1st number × 5 - 3 = 2nd number.

Now,

For, 17 : 82

⇒ 17 × 5 - 3

⇒ 85 - 3 = 82.

For, 31 : 158

⇒ 31 × 5 + 3

⇒ 155 + 3 = 158.

For, 19 : 92

⇒ 19 × 5 - 3

⇒ 95 - 3 = 92.

For, 47 : 232

⇒ 47 × 5 - 3

⇒ 235 - 3 = 232.

Here, Option 1 '31 : 158' is different from the given pairs.

Hence, the correct answer is "Option 1".

Given:

A number is decreased by 20% to get another number.

The number so obtained is increased by 200% to get a third number.

Concept used:

Incremented/Reduced value = Initial value (1 ± change%)

Calculation:

Let the first number be Q.

Second number = Q(1 - 20%) = 0.8Q

Third number = 0.8Q(1 + 200%) = 2.4Q

The difference between the third number and the original number = 2.4Q - Q = 1.4Q

The difference between the second and third number = 2.4Q - 0.8Q = 1.6Q

Now, % less = \(\frac {1.6Q - 1.4Q}{1.6Q} \times 100\%\) = 12.5%

∴ The difference between the third number and the original number is 12.5% less than the difference between the second and the third number.

Given:

Number p is 15% more than 150. If k is 15% less than p

Calculation:

P = 150 × 115%

⇒ 172.5

Now,

k = 172.5 × 85%

⇒ 146.625

∴ The required answer is 146.625.

Given:

Number p is 15% more than 150. If k is 15% less than p

Calculation:

P = 150 × 115%

⇒ 172.5

Now,

k = 172.5 × 85%

⇒ 146.625

∴ The required answer is 146.625.

Given:

A number is decreased by 20% to get another number.

The number so obtained is increased by 200% to get a third number.

Concept used:

Incremented/Reduced value = Initial value (1 ± change%)

Calculation:

Let the first number be Q.

Second number = Q(1 - 20%) = 0.8Q

Third number = 0.8Q(1 + 200%) = 2.4Q

The difference between the third number and the original number = 2.4Q - Q = 1.4Q

The difference between the second and third number = 2.4Q - 0.8Q = 1.6Q

Now, % less = \(\frac {1.6Q - 1.4Q}{1.6Q} \times 100\%\) = 12.5%

∴ The difference between the third number and the original number is 12.5% less than the difference between the second and the third number.

The logic followed here is:

Logic: 1st number × 5 - 3 = 2nd number.

Now,

For, 17 : 82

⇒ 17 × 5 - 3

⇒ 85 - 3 = 82.

For, 31 : 158

⇒ 31 × 5 + 3

⇒ 155 + 3 = 158.

For, 19 : 92

⇒ 19 × 5 - 3

⇒ 95 - 3 = 92.

For, 47 : 232

⇒ 47 × 5 - 3

⇒ 235 - 3 = 232.

Here, Option 1 '31 : 158' is different from the given pairs.

Hence, the correct answer is "Option 1".

Given:

Number p is 15% more than 150. If k is 15% less than p

Calculation:

P = 150 × 115%

⇒ 172.5

Now,

k = 172.5 × 85%

⇒ 146.625

∴ The required answer is 146.625.

Given:

A number is decreased by 20% to get another number.

The number so obtained is increased by 200% to get a third number.

Concept used:

Incremented/Reduced value = Initial value (1 ± change%)

Calculation:

Let the first number be Q.

Second number = Q(1 - 20%) = 0.8Q

Third number = 0.8Q(1 + 200%) = 2.4Q

The difference between the third number and the original number = 2.4Q - Q = 1.4Q

The difference between the second and third number = 2.4Q - 0.8Q = 1.6Q

Now, % less = \(\frac {1.6Q - 1.4Q}{1.6Q} \times 100\%\) = 12.5%

∴ The difference between the third number and the original number is 12.5% less than the difference between the second and the third number.

LOGIC: The sum of the first three numbers is equal to the last number.

In 1157 →

⇒ 1 + 1 + 5

⇒ 7

In 2305 →

⇒ 2 + 3 + 0

⇒ 5

In 6309 →

⇒ 6 + 3 + 0 

⇒ 9

In 1236 →

⇒ 1 + 2 + 3 

⇒ 6

Now, check the options one by one,

1) In 2338 →

⇒ 2 + 3 + 3 

⇒ 8

2) In 3148 →

⇒ 3 + 1 + 4

⇒ 8

3) In 3246 →

⇒ 3 + 2 + 4

⇒ 9

4) In 1214 →

⇒ 1 + 2 + 1

⇒ 4

Hence, the correct answer is 3246.

LOGIC: First two digits ÷ Third digit = Forth digit

In 1427 →

⇒ 14 ÷ 2

⇒ 7

In 2555 → 

⇒ 25 ÷ 5

⇒ 5

In 4595 →

⇒ 45 ÷ 9

⇒ 5

In 1836 → 

⇒ 18 ÷ 3

⇒ 6

Now, check the options one by one,

In 1892 →

⇒ 18 ÷ 9

⇒ 2

In 7289 →

⇒ 72 ÷ 8

⇒ 9

In 8198 →

⇒ 81 ÷ 9

⇒ 9

In 1644 →

⇒ 16 ÷ 4

⇒ 4

Hence, the correct answer is 8198.

The logic follows here is:

In 202 - 40

⇒ 20 × 2 

⇒ 40

In 305 - 150

⇒ 30 × 5

⇒ 150

In 120 - 0

⇒ 12 × 0 

⇒ 0

Now, check the options one by one,

1) In 132 - 26

⇒ 13 × 2

⇒ 26

2) In 152 - 31

⇒ 15 × 2

⇒ 30 

3) In 241 - 24

⇒ 24 × 1

⇒ 24

4) In 223 - 66

⇒ 22 × 3

⇒ 66

Hence, the correct answer is 152 - 31.

The logic followed here is:

Logic: 1st number × 5 - 3 = 2nd number.

Now,

For, 17 : 82

⇒ 17 × 5 - 3

⇒ 85 - 3 = 82.

For, 31 : 158

⇒ 31 × 5 + 3

⇒ 155 + 3 = 158.

For, 19 : 92

⇒ 19 × 5 - 3

⇒ 95 - 3 = 92.

For, 47 : 232

⇒ 47 × 5 - 3

⇒ 235 - 3 = 232.

Here, Option 1 '31 : 158' is different from the given pairs.

Hence, the correct answer is "Option 1".

LOGIC: The first number is a cube of the second number.

In 216 - 6 →

⇒ 6³  

⇒ 216

In 1331 - 11 →

⇒ 11³ 

⇒ 1331 

In 729 - 9 →

⇒ 9³

⇒ 729

Now, check the options one by one,

In 1000 - 10 →

⇒ 10³ 

⇒ 1000

In 512 - 7 →

⇒ 7³

⇒ 343

In 64 - 4 →

⇒ 4³

⇒ 64

In 1728 - 12 →

⇒ 12³

⇒ 1728

Hence, the correct answer is 512 - 7.