The Traveling Electromagnetic Wave MCQ Quiz - Objective Question with Answer for The Traveling Electromagnetic Wave - Download Free PDF
Last updated on May 30, 2025
Latest The Traveling Electromagnetic Wave MCQ Objective Questions
The Traveling Electromagnetic Wave Question 1:
The electric field of an EM wave in free space is given by E = 10 cos (10⁷t + kx) V/m where t and x are in sec and meter respectively. It can be inferred that:
(A) The wavelength λ is 188.4 m
(B) The wave number k is 0.33 rad/m
(C) The wave amplitude is 10 V/m
(D) The wave is propagating along the +x direction
Which of the following pairs of statements are correct?
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 1 Detailed Solution
Solution:
We are given the equation for the electric field of an electromagnetic wave in free space:
E = 10 cos(10⁷t + kx) V/m, where t is in seconds and x is in meters.
By comparing the given equation with the standard form of the equation for a wave, we can deduce the following:
The amplitude E₀ = 10 V/m.
The angular frequency ω = 10⁷ rad/s.
Now, the wave velocity (c) is related to the wavelength (λ) by the equation:
c = vλ / 2π
Solving for λ (wavelength):
λ = 2πc / ω = (2π * 3 × 10⁸) / 10⁷ = 188.4 m
Next, the wave number k is related to the wavelength by the formula:
k = ω / c = 10⁷ / (3 × 10⁸) = 0.033 rad/m
Thus, the wavelength λ is 188.4 m and the wave number k is 0.033 rad/m. The amplitude is 10 V/m.
Additionally, the wave propagates along the y-direction (as indicated by the positive sign in the argument of the cosine function), not along the x-direction as stated in the options.
Therefore, the correct pair of statements are: (A) and (C).
The Traveling Electromagnetic Wave Question 2:
An electromagnetic wave travels in a medium with a speed of 2 × 10⁸ ms⁻¹. The relative permeability of the medium is 1. Then the relative permittivity is
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 2 Detailed Solution
Concept:
The speed of an electromagnetic wave in a medium is related to the permittivity (ε) and permeability (μ) of the medium by the equation:
v = 1 / √(ε₀ εr μ₀ μr),
where:
- v is the speed of the wave in the medium,
- ε₀ is the permittivity of free space,
- μ₀ is the permeability of free space,
- εr is the relative permittivity of the medium,
- μr is the relative permeability of the medium.
For free space, ε₀ = 8.854 × 10⁻¹² F/m and μ₀ = 4π × 10⁻⁷ H/m.
Calculation:
Given, speed of the wave, v = 2 × 10⁸ m/s and μr = 1.
Using the relation for wave speed:
v = 1 / √(ε₀ εr μ₀ μr)
Substitute the known values:
2 × 10⁸ = 1 / √(8.854 × 10⁻¹² × εr × 4π × 10⁻⁷ × 1)
2 × 10⁸ = 1 / √(1.112 × 10⁻¹⁸ × εr)
Squaring both sides:
(2 × 10⁸)² = 1 / (1.112 × 10⁻¹⁸ × εr)
4 × 10¹⁶ = 1 / (1.112 × 10⁻¹⁸ × εr)
εr = (1.112 × 10⁻¹⁸) / (4 × 10¹⁶)
εr = 2.25
∴ The relative permittivity εr is 2.25. Option 3) is correct.
The Traveling Electromagnetic Wave Question 3:
When the phase velocity of an electromagnetic wave depends on frequency in any medium, the phenomenon is called
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 3 Detailed Solution
Explanation:
Dispersion occurs when the phase velocity of an electromagnetic wave depends on its frequency. This causes different frequency components of a wave to travel at different speeds in the medium, leading to phenomena such as the separation of white light into its constituent colors in a prism.
Thus, option '2' is correct.
The Traveling Electromagnetic Wave Question 4:
An electromagnetic wave going through free space is described by E = E0 sin(kx - ωt), B = B0 sin (kx - ωt), then -
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 4 Detailed Solution
Calculation:
We are given that an electromagnetic wave traveling through free space is described by the electric field E and the magnetic field B as follows:
E = E0 sin(kx - ωt)
B = B0 sin(kx - ωt)
We need to determine the correct relationship between the amplitudes E0 and B0.
For an electromagnetic wave traveling through free space, the magnitudes of the electric field and magnetic field are related by the speed of light c:
c = E0 / B0
where c is the speed of light in free space.
We also know that for a wave, the wave number k and the angular frequency ω are related to the speed of light by:
c = ω / k
Combining these two equations, we get:
E0 / B0 = ω / k
Rearranging this equation, we find the relationship:
E0 k = B0 ω
Therefore, the correct answer is:
Option 1: E0 k = B0 ω
Final Answer: The correct relationship is E0 k = B0 ω, which corresponds to Option 1.
The Traveling Electromagnetic Wave Question 5:
The electric field in an electromagnetic wave is given by E = 56.5 sinω(t – x/c) NC–1. Find the intensity of the wave if it is propagating along x-axis in the free space.
(Given ∈0 = 8.85 × 10–12C2N–1m–2)
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 5 Detailed Solution
Concept:
The intensity I of an electromagnetic wave is related to the peak electric field Eo by the formula:
\(I=\frac{1}{2} \varepsilon_0 E_0^2 c\)
Calculation:
⇒ I = \(\frac{1}{2} 8.5 \times 10^{-12} \times(56.5)^2 \times 3 \times 10^8\)
⇒ I = 4.24 W/m2
∴ the Correct answer is Option (2): 4.24 Wm–2
Top The Traveling Electromagnetic Wave MCQ Objective Questions
Light year is a measure of
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 6 Detailed Solution
Download Solution PDFThe correct answer is Distance.
Concept:
Light year:
- The distance travelled by light in one year is called as light year.
- It is the unit of astronomical distance.
- 1 light year = 9.461 trillion kilometers which is a very large distance.
Explanation:
- As light year is the distance travelled by light in a year so light year is a unit of distance. Hence option 2 is correct.
Important points:
- We can measure a very large distance with the help of light year. Thus light year is a unit for measurement of very large distance.
The electric and magnetic fields in electromagnetic waves are oriented-
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 7 Detailed Solution
Download Solution PDFCONCEPT:
- The electric field is always perpendicular to the magnetic field, and both fields are directed at right-angles to the direction of propagation of the wave.
- The wave propagates in the direction E × B. Electromagnetic waves are a type of transverse wave.
EXPLANATION:
- In electromagnetic waves the electric field is always perpendicular to the magnetic field and both field are directed at right –angles to the direction of propagation of the wave.
So option 4 is correct.
Which of the following wave has maximum speed in vacuum?
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 8 Detailed Solution
Download Solution PDFCONCEPT:
Electromagnetic waves or EM waves:
- The waves that are formed as a result of vibrations between an electric field and a magnetic field and they are perpendicular to each other and to the direction of the wave is called an electromagnetic wave.
- The accelerating charged particle produces an electromagnetic (EM) wave.
- A charged particle oscillating about an equilibrium position is an accelerating charged particle.
- Electromagnetic waves do not require any matter to propagate from one place to another as it consists of photons. They can move in a vacuum.
Properties of electromagnetic waves:
- Not have any charge or we can say that they are neutral.
- Propagate as a transverse wave.
- They move with the velocity the same as that of light.
- The speed of all the electromagnetic waves is 3×108 m/s in a vacuum.
- It contains energy and they also contain momentum.
- They can travel in a vacuum also.
EXPLANATION:
- We know that x-rays, ultraviolet rays, and gamma rays are electromagnetic waves.
- The speed of all the electromagnetic waves is 3 × 108 m/s in a vacuum. Hence, option 4 is correct.
Which of the following is NOT the characteristic of electromagnetic waves?
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 9 Detailed Solution
Download Solution PDFCONCEPT:
- Electromagnetic waves or EM waves: The waves that are formed as a result of vibrations between an electric field and a magnetic field and they are perpendicular to each other and to the direction of the wave is called an electromagnetic waves.
- The accelerating charged particle produces an electromagnetic (EM) wave.
- A charged particle oscillating about an equilibrium position is an accelerating charged particle.
- Electromagnetic waves do not require any matter to propagate from one place to another as it consists of photons. They can move in a vacuum.
Properties of electromagnetic waves:
- The electromagnetic waves are neutral.
- Propagate as a transverse wave.
- They move with a velocity the same as that of light i.e 3 × 108 m/s.
- It contains energy and also contains momentum.
- They can travel in a vacuum also.
Characteristics of Electromagnetic waves:
- The accelerated charge particles are the source of electromagnetic waves.
- Electromagnetic waves are transverse in nature as they propagate by varying the electric and magnetic fields such that the two fields are perpendicular to each other.
- Electromagnetic waves have constant velocity in vacuum
- Electromagnetic wave propagation does not require any material medium to travel.
- Electromagnetic waves follow the principle of superposition.
- Electromagnetic waves are not reflected by an electric or magnetic field.
Explanation:
- Hence we can see that Moving charges are not responsible to produce electromagnetic waves,
- Instead Accelerated charges are responsible to produce electromagnetic waves.
Which of the following properties is/are possible in case of X-rays ?
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 10 Detailed Solution
Download Solution PDFCONCEPT:
- Electromagnetic spectrum: It is a collection of a range of different waves in sequential order from radio to gamma electromagnetic waves.
Properties of X-ray:
- X-rays are electromagnetic waves with wavelength range 0. 1Å – 100Å.
- The wavelength of X-rays is small in comparison to the wavelength of the light. Hence they carry more energy.
- They are invisible.
- They travel in a straight line with the speed of light.
- X-rays are measured in Rontgen (a measure of ionization power).
- X-rays carry no charge so they are not reflected in the magnetic field and electric field.
- They ionize gases.
- They produce photoelectric effect and Compton effect
- These cannot be used in Radar because they are not reflected by the target.
- They show all the important properties of light rays like reflection, refraction, interference, diffraction, and polarization, etc.
EXPLANATION:
- From above it is clear that due to the high penetrating power of X – rays, it shows all the important properties of light rays like reflection, refraction, interference, diffraction, and polarization, etc. Therefore option 4 is correct.
Which of the following remains same for all electromagnetic waves?
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 11 Detailed Solution
Download Solution PDFThe correct answer is option 3) i.e. Velocity
CONCEPT:
- Electromagnetic spectrum: It is the arrangement of electromagnetic radiations according to their frequency or wavelength.
- The electromagnetic spectrum has a range of frequencies, wavelengths, and photon energies.
- Typically, electromagnetic waves travel at the speed of light in a vacuum.
- The electromagnetic spectrum is as follows:
EXPLANATION:
- The velocity of an electromagnetic wave (c) in a vacuum is related to its wavelength (λ) and frequency (f) as follows:
f λ = c
- As we go from gamma rays to radio waves, the frequency decreases, and the wavelength increases.
- Hence, the velocity (c = 3 × 108 m/s) is constant.
Which of the following phenomenon differentiate the electromagnetic waves and sound waves?
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 12 Detailed Solution
Download Solution PDFThe correct option is 4.
CONCEPT:
Longitudinal wave motion:
- It is that wave motion in which individual particles of the medium execute simple harmonic motion about their mean position along the same direction, in which the wave is propagated.
- For example Sound waves.
Transverse wave motion:
- The vibration of particles in a medium and the propagation of waves are perpendicular to each other.
- Example: Waves in the surface of the water, waves in a string, Electromagnetic waves, etc.
Polarization:
- This is a process by which unpolarised light is transformed into polarized light.
- Polarisation tells about the wave nature of light, as the light wave is polarised in a particular plane.
- The longitudinal waves cannot be polarised.
EXPLANATION:
- The sound wave is a longitudinal wave that can't be polarised.
- The electromagnetic wave is a transverse wave and it can be polarised.
- Thus the polarisation differentiates the electromagnetic waves and sound waves.
The ratio of the amplitude of the magnetic field to the amplitude of the electric field for electromagnetic wave propagation in a vacuum is equal to
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 13 Detailed Solution
Download Solution PDFConcept:
In electromagnetic waves, the ratio of amplitudes of the electric field and the magnetic field is equal to the velocity of the electromagnetic waves in free space.
\(\frac{{{E_0}}}{{{B_0}}} = c\)
\(\frac{{{B_0}}}{{{E_0}}} = \frac{1}{c}\)
Where:
E0 = Electric field
B0 = Magnetic field
c = velocity
Derivation:
The intrinsic impedance of the wave is defined as the ratio of the electric field and the magnetic field phasor (complex amplitude), i.e.
\(\frac{{\left| E \right|}}{{\left| H \right|}} = \eta = \sqrt {\frac{\mu }{\epsilon}} \)
Since B = μ H
\(H = \frac{B}{\mu }\)
\(\frac{{\left| E \right|}}{{\left| B \right|}}\mu = \sqrt {\frac{\mu }{\epsilon}}\)
\(\frac{{\left| E \right|}}{{\left| B \right|}} = \sqrt {\frac{1}{{\mu\epsilon }}}\)
\(c = \frac{1}{{\sqrt {{\mu _0}{\epsilon_o}} }},\;\frac{{\left| E \right|}}{{\left| B \right|}} = c\)
The light has ____ nature.
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 14 Detailed Solution
Download Solution PDFCONCEPT:
- Light: It is an electromagnetic wave.
- Light shows dual nature i.e. wave and particle.
Phenomenon explaining the wave nature of light is/are:
- Interference
- Diffraction
- Polarisation
Phenomenons explaining the particle nature of light are:
- Photoelectric effect
- Compton Scattering
- Photons associated with light shows that the energy is Quantised and occurs in discrete levels.
EXPLANATION:
- From the above discussion, the light has a dual nature. So option 4 is correct.
Who discovered Electromagnetic waves?
Answer (Detailed Solution Below)
The Traveling Electromagnetic Wave Question 15 Detailed Solution
Download Solution PDFCONCEPT:
- Electromagnetic waves: It is a transverse wave defined as composed of oscillating electrical and magnetic fields perpendicular (90°) to each other.
- The Speed of electromagnetic waves is the same as of speed of light c = 3 × 108 m/s.
EXPLANATION:
- James Clerk Maxwell: He is a Scottish Mathematical physicist. He proposed equations of Magnetism (Maxwell’s equations of electromagnetism) and predicted that electromagnetic waves exist but didn’t discover it.
- Heinrich Rudolf Hertz: He is a German physicist who conclusively proved the existence of electromagnetic waves. The unit of frequency, Cycles per second was named Hertz in his honour.
- Michael Faraday: He is an English Scientist who discovered principles of Electromagnetic induction, Electrolysis and Diamagnetism. The SI Unit of capacitance is Farad in his honour
- Hans Christian Oersted: He was a Danish physicist who finds out that electric current creates a magnetic field.
So, Option 2 is correct.