Transmission Lines MCQ Quiz in मल्याळम - Objective Question with Answer for Transmission Lines - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Last updated on Mar 9, 2025

നേടുക Transmission Lines ഉത്തരങ്ങളും വിശദമായ പരിഹാരങ്ങളുമുള്ള മൾട്ടിപ്പിൾ ചോയ്സ് ചോദ്യങ്ങൾ (MCQ ക്വിസ്). ഇവ സൗജന്യമായി ഡൗൺലോഡ് ചെയ്യുക Transmission Lines MCQ ക്വിസ് പിഡിഎഫ്, ബാങ്കിംഗ്, എസ്എസ്‌സി, റെയിൽവേ, യുപിഎസ്‌സി, സ്റ്റേറ്റ് പിഎസ്‌സി തുടങ്ങിയ നിങ്ങളുടെ വരാനിരിക്കുന്ന പരീക്ഷകൾക്കായി തയ്യാറെടുക്കുക

Latest Transmission Lines MCQ Objective Questions

Top Transmission Lines MCQ Objective Questions

Transmission Lines Question 1:

The dielectric constant of the material used in a transmission line is 2. What is the velocity factor of this line if its characteristic impedance is 300 Ω?

  1. 70.7%
  2. 75%
  3. 1.414
  4. 150

Answer (Detailed Solution Below)

Option 1 : 70.7%

Transmission Lines Question 1 Detailed Solution

Concept:

Velocity factor

  • The velocity of light and all other electromagnetic waves depends on the medium through which they travel.
  • It is very nearly 3 × 108 m/s in a vacuum and slower in all other media.

The velocity of light in a medium is given by

\(v = \frac{{{v_c}}}{{\sqrt k }}\)

v: velocity of the wave in the medium

vc: velocity of the wave in free space

k: dielectric constant

The velocity factor of a dielectric substance, and thus of a cable, is the velocity reduction ratio and is therefore given by

\(vf = \frac{1}{{\sqrt k }}\)

The dielectric constants of materials commonly used in transmission lines range from about 1.2 to 2.8, giving corresponding velocity factors from 0.9 to 0.6

NOTE:

since ν = fλ and f is constant, the wavelength λ is also reduced by a ratio equal to the velocity factor.

Example

If a section of 300-Ω twin lead has a velocity factor of 0.82, the speed of energy transferred is 18 per cent slower than in a vacuum.

Calculation:

Given dielectric constant is 2.

The velocity factor of the line is

\(vf = \frac{1}{{\sqrt 2 }}\)

vf = 0.707

vf = 70.7%

Transmission Lines Question 2:

Which one of the following statement is not correct for a lossless transmission line?

  1. Attenuation constant of a lossless line is always zero.
  2. Propagation constant of a lossless line is always real.
  3. Characteristic impedance of a lossless line is real.
  4. Both (1) and (3)

Answer (Detailed Solution Below)

Option 2 : Propagation constant of a lossless line is always real.

Transmission Lines Question 2 Detailed Solution

Concept:

Characteristic Impedance of a transmission line is defined as:

\(Z_0=\sqrt{{\frac{R+jω L}{G+jω C}}}\)   --- (1)

R = Resistance per unit length of the line

G = Conductance per unit length of the line

L = Inductance per unit length of the line

C = Capacitance per unit length of the line

and the propagation constant of the line is given by:

\(\gamma=\sqrt{(R+jω L)(G+jω C)}\)   ---(2)

This can be written as:

γ = α + jβ

α = attenuation constant

β = phase constant

For a lossless line,

R = G = 0

Using Equation (1), the characteristic impedance of the lossless transmission line will become:

\(Z_0=\sqrt{{\frac{ L}{C}}}\)

Using Equation (2), the propagation constant of the lossless transmission line will become:

\(\gamma =j\omega \sqrt{LC}\)

\(\alpha=0,~\beta=\omega \sqrt{LC}\)

Observation:

  • The characteristic impedance of a lossless line is real.
  • The attenuation constant of a lossless transmission line is always zero.

Transmission Lines Question 3:

The Characteristic impedance of transmission line

  1. Increases with increase in length
  2. Decreases with length of line
  3. Independent of Line Length
  4. None of these

Answer (Detailed Solution Below)

Option 3 : Independent of Line Length

Transmission Lines Question 3 Detailed Solution

The Characteristic impedance of the transmission line is given as:

\({Z_0} = \sqrt {\frac{{R + j\omega L\;}}{{G + j\omega C}}}\)

Hence it is independent of the length of the transmission line.

Transmission Lines Question 4:

In case the characteristic impedance of a transmission line is equal to the load impedance

  1. the system will resonate badly
  2. all the energy sent will be absorbed by the load
  3. all the energy sent will pass to the earth
  4. all the energy will be lost in transmission line as transmission losses

Answer (Detailed Solution Below)

Option 2 : all the energy sent will be absorbed by the load

Transmission Lines Question 4 Detailed Solution

It is always desirable to have a perfectly matched load for maximum power transfer, i.e. ZL = Z0

Concept:

The reflection coefficient of the transmission line at the load is given by:

\({\rm{Γ }} = \frac{{{{\rm{Z}}_{\rm{L}}} - {Z_0}}}{{{Z_L} + {Z_0}}}\)

ZL = Load impedance

Z0 = Characteristic Impedance

For a perfectly matched load:

ZL = Z0

The reflection coefficient is:

\({\rm{Γ }} = \frac{{{{\rm{Z}}_{\rm{0}}} - {Z_0}}}{{{Z_0} + {Z_0}}}=0\)

This indicates that all the power is transferred to the load and there is no reflected power, i.e. all the energy sent will be absorbed by the load.

Transmission Lines Question 5:

A 75 Ω transmission line is first short-terminated and the minima locations are noted. When the short is replaced by a resistive load RL, the minima locations are not altered and the VSWR is measured to be 3. The value of RL is

  1. 25 Ω 
  2. 50 Ω 
  3. 225 Ω 
  4. 250 Ω 

Answer (Detailed Solution Below)

Option 1 : 25 Ω 

Transmission Lines Question 5 Detailed Solution

Concept:

Voltage standing wave ratio: It is the ratio of maximum voltage to minimum voltage.

If the voltage minima occur at load ZL < Z0 then

\(VSWR = \frac{{{Z_0}}}{{{Z_L}}}\)

If the voltage maxima occur at load ZL > Z0 then

\(VSWR = \frac{{{Z_L}}}{{{Z_0}}}\)

Analysis:

Z0 = 75 Ω 

When the load is shorted the voltage minima occur at the load, and it does not change even when short is replaced by RL

\(VSWR = \frac{Z_0}{R_L}\) and RL < Z0 

VSWR = 3

\(\frac{75}{R_L} = 3\)

RL = 25 Ω 

Transmission Lines Question 6:

A 100 V peak signal at 1 GHz is applied to a transmission line of characteristic impedance 100 Ω, terminated with an antenna of 75 Ω. The peak values of reflected and incident currents are: 

  1. 0.142 A, 1 A
  2. 0.284 A, 1 A
  3. 0.142 A, 2 A
  4. 1 A, 0.142 A

Answer (Detailed Solution Below)

Option 1 : 0.142 A, 1 A

Transmission Lines Question 6 Detailed Solution

Concept:

If a transmission line will characteristic impedance Z0 is terminated at a load impedance ZL then the reflection coefficient at the load is given by:

\({{\rm{\Gamma }}_L} = \frac{{{Z_L} - {Z_0}}}{{{Z_L} + {Z_0}}}\)

ZL = Load Impedance

Z0 = Characteristic Impedance

Calculation:

Given:

F2 Shubham Madhu 10.08.20 D1

Since a voltage signal of 100V with 1 GHz frequency is applied to the transmission line with Z0 = 100 Ω, we get:

\(I = \frac{{100\;V}}{{100\;{\rm{\Omega }}}} = 1\;A\)

For the antenna, this current will be the incident current.

But due to the impedance mismatch between the transmission line and the antenna, part of the current will be reflected.

Reflection coefficient will be:

\({{\rm{\Gamma }}_L} = \frac{{{Z_A} - {Z_0}}}{{{Z_n} + {Z_0}}} = \frac{{75 - 100}}{{75 + 100}} = - \frac{1}{7}\)

The peak value of the reflected current will be:

\({I_{ref}} = \left| {{{\rm{\Gamma }}_L}} \right| \times {I_{inc}}\)

\( = \frac{1}{7} \times 1\;A \approx 0.142\;A\)

Transmission Lines Question 7:

Which of the following is used for impedance inversion in a transmission line?

  1. Short Circuited stub 
  2. Open Circuited Stub
  3. Balum Transformer
  4. Quarter wave line 

Answer (Detailed Solution Below)

Option 4 : Quarter wave line 

Transmission Lines Question 7 Detailed Solution

  • The load impedance, Zat the end of the transmission line must match to its characteristic impedance, Z0 Otherwise there will be reflections from the transmission line’s end.
  • A quarter-wave transformer is a component that can be inserted between the transmission line and the load to match the load impedance ZL to the transmission line’s characteristic impedance Z0.
  • The input impedance of a quarter-wave transformer is given as:

           \({{\rm{Z}}_{{\rm{in}}}} = \frac{{{\rm{Z}}_0^2}}{{{{\rm{Z}}_{\rm{L}}}}}\;\).

F1 S.B Deepak 06.03.2020 D3

Observation:

We observe that when ZL is low i.e. zero then Zin will be High i.e. Infinity and vice versa.

Transmission Lines Question 8:

A transmission line of \(50{\rm{\;\Omega }}\) characteristic impedance is terminated with a \(\rm 100 \ Ω\) resistance. The minimum impedance measured on the line is equal to

  1. 0 Ω
  2. 25 Ω
  3. 50 Ω
  4. 100 Ω

Answer (Detailed Solution Below)

Option 2 : 25 Ω

Transmission Lines Question 8 Detailed Solution

Concept:

The maximum and minimum impedance across a transmission line is defined as:

Maximum impedance:

Zmax = Z0 × VSWR

Minimum impedance:

\({Z_{min}} = \frac{{{Z_0}}}{{VSWR}}\)

VSWR = Voltage standing wave ratio given by:

\(VSWR = \frac{{1 + \left| {{{\rm{\Gamma }}}} \right|}}{{1 - \left| {{{\rm{\Gamma }}}} \right|}}\)

Γ = Reflection Coefficient

Calculation:

Given:

Z0 = 50Ω 

ZL = 100Ω 

\(\left| {\rm{\Gamma }} \right| = \frac{{{Z_L} - {Z_0}}}{{{Z_L} + {Z_0}}}\)

\(\left| {\rm{\Gamma }} \right| = \frac{{100 - 50}}{{100 +50 }}\)

\(\left| {\rm{\Gamma }} \right| = \frac{1}{3}\)

\(VSWR = \frac{{1 + \left| {\rm{\Gamma }} \right|}}{{1 - \left| {\rm{\Gamma }} \right|}}\)

\(= \frac{{1 + \frac{1}{3}}}{{1 - \frac{1}{3}}} = 2\)

Zmax = Z0 × VSWR

Zmax = 50 × 2 = 100Ω

\({Z_{min}} = \frac{{{Z_0}}}{VSWR} = \frac{{50}}{2}\)

Zmin = 25Ω 

∴ The minimum Impedance on line is 25Ω.

Transmission Lines Question 9:

The real part of propagation constant of a transmission line is

  1. Phase constant
  2. Attenuation constant
  3. Stability constant
  4. Reliability factor

Answer (Detailed Solution Below)

Option 2 : Attenuation constant

Transmission Lines Question 9 Detailed Solution

Concept:

The propagation constant of a transmission line is a complex quantity given by:

γ = α + jβ

α = Attenuation constant, related to the line parameters as:

\(\alpha = \sqrt {RC}\)

β = Phase constant, related to the line parameters as:

\(\beta = {\rm{ω }}\sqrt {{\rm{LC}}} \)

For a loss lossless line, there is no attenuation, i.e. α = 0. The propagation constant will become:

γ = jβ

|γ| = |β|

26 June 1

Attenuation constant:

  • Attenuation constant gives attenuation of an electromagnetic wave propagating through a medium per unit distance from the source.
  • It is the real part of the propagation constant and is measured in nepers per metre.


Phase Constant:

  • The phase constant is the imaginary component of the propagation constant for a plane wave
  • It represents the change in phase per unit length along the path travelled by the wave at any instant
  • Phase constant is measured in radians per unit length

Transmission Lines Question 10:

If L and C are inductance per unit length and capacitance per unit length of a lossless transmission line, then the velocity of propagation(v) on this line is given by

  1. v = √( L)/C
  2. v = 1 / √( LC)
  3. v = √(L/C)
  4. none of the above

Answer (Detailed Solution Below)

Option 2 : v = 1 / √( LC)

Transmission Lines Question 10 Detailed Solution

The velocity of propagation is given as:

\({{\rm{v}}_{\rm{p}}} = \frac{1}{{\sqrt { {{\rm{LC}}}} }}\)

R = Resistance of the line per unit length.

L = Inductance of the line per unit length.

C = Capacitance per unit length.

Note:

Propagation constant is given by:

\({\rm{\gamma }} = \sqrt {\left( {{\rm{R}} + {\rm{j\;\omega L}}} \right)\left( {{\rm{G}} + {\rm{j\;\omega }}C} \right)}\)

Phase shift constant is given by:

 \({\rm{\beta }} = {\rm{\omega }}\sqrt {{\rm{LC}}}\)

Characteristic impedance is given by:

\({{\rm{Z}}_0} = \sqrt {\frac{{\rm{L}}}{{\rm{C}}}}\)
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