Logical Connectives MCQ Quiz in தமிழ் - Objective Question with Answer for Logical Connectives - இலவச PDF ஐப் பதிவிறக்கவும்
Last updated on Mar 23, 2025
பெறு Logical Connectives பதில்கள் மற்றும் விரிவான தீர்வுகளுடன் கூடிய பல தேர்வு கேள்விகள் (MCQ வினாடிவினா). இவற்றை இலவசமாகப் பதிவிறக்கவும் Logical Connectives MCQ வினாடி வினா Pdf மற்றும் வங்கி, SSC, ரயில்வே, UPSC, மாநில PSC போன்ற உங்களின் வரவிருக்கும் தேர்வுகளுக்குத் தயாராகுங்கள்.
Latest Logical Connectives MCQ Objective Questions
Top Logical Connectives MCQ Objective Questions
Logical Connectives Question 1:
Consider the following TRUTH table:
|
Y |
Z |
Y □ Z |
|
0 |
0 |
0 |
|
0 |
1 |
1 |
|
1 |
0 |
0 |
|
1 |
1 |
0 |
|
Y |
Z |
Y ⊗ Z |
|
0 |
0 |
1 |
|
0 |
1 |
0 |
|
1 |
0 |
1 |
|
1 |
1 |
0 |
(p □ q) ∨ (p ⊗ q) ≡
Answer (Detailed Solution Below)
Option 1 : \(p \to \bar q\)
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Logical Connectives Question 1 Detailed Solution
\(\begin{array}{l} p\; □ \;q \equiv \bar pq\\ p ⊗ q = \bar q\\ \therefore \bar pq + \bar q = \left( {\bar p + \bar q} \right)\left( {q + \bar q\;} \right) \equiv \bar p + \bar q\\ \equiv p \to \bar q \end{array}\)
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Logical Connectives Question 2:
Diamonds and pearls are precious.
WFF for this statement is:
Given
D(x) : x is a diamond
P (x) : x is a pearl
T(x) : x is preciousAnswer (Detailed Solution Below)
Option 2 : \(\forall x\left[ {\left( {D\left( x \right) \vee P\left( x \right)} \right) \to T\left( x \right)} \right]\)
Logical Connectives Question 2 Detailed Solution
If x is either a diamond or a pearl then it’s is precious.
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Logical Connectives Question 3:
Consider the following Truth Table
|
A |
B |
Y |
|
0 |
0 |
0 |
|
0 |
1 |
1 |
|
1 |
0 |
0 |
|
1 |
1 |
1 |
Y =
Answer (Detailed Solution Below)
Option 2 : B
Logical Connectives Question 3 Detailed Solution
AB + B = (A + 1)B = B
Also Y = B
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Logical Connectives Question 4:
|
A |
B |
F(A, B) |
|
F |
F |
T |
|
F |
T |
T |
|
T |
F |
F |
|
T |
T |
T |
From the given truth table F(A, B) is equivalent to:
Answer (Detailed Solution Below)
Option 1 : \(\bar B \to \bar A\)
Logical Connectives Question 4 Detailed Solution
\(F\left( {A,B} \right) \equiv A \to B \equiv \bar B \to \bar A\)
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