Percentages MCQ Quiz in தமிழ் - Objective Question with Answer for Percentages - இலவச PDF ஐப் பதிவிறக்கவும்

Last updated on Mar 17, 2025

பெறு Percentages பதில்கள் மற்றும் விரிவான தீர்வுகளுடன் கூடிய பல தேர்வு கேள்விகள் (MCQ வினாடிவினா). இவற்றை இலவசமாகப் பதிவிறக்கவும் Percentages MCQ வினாடி வினா Pdf மற்றும் வங்கி, SSC, ரயில்வே, UPSC, மாநில PSC போன்ற உங்களின் வரவிருக்கும் தேர்வுகளுக்குத் தயாராகுங்கள்.

Latest Percentages MCQ Objective Questions

Top Percentages MCQ Objective Questions

Percentages Question 1:

An electronic store marks up a gadget by \(300\%\) of its cost price, and later reduces it by \(85\%\) for a sale. What is the final price as a percentage of the original cost?

  1. 15%
  2. 45%
  3. 45%
  4. 30%

Answer (Detailed Solution Below)

Option 3 : 45%

Percentages Question 1 Detailed Solution

The gadget's price is initially marked up by \(300\%\) making it \(400\%\) of its cost (\(100\%\) + \(300\%\)). The \(85\%\) reduction is then applied to this price, resulting in \(400 \times (1 - 0.85) = 400 \times 0.15 = 60\). Thus, the final price is \(60\%\) of the original cost. Therefore, the correct answer is \(60\%\).

Percentages Question 2:

A car is purchased for $25,000 and depreciates by 10% each year. What is the car's value after 4 years?

  1. $16,405
  2. $18,000
  3. $20,000
  4. $22,500

Answer (Detailed Solution Below)

Option 1 : $16,405

Percentages Question 2 Detailed Solution

To find the car's value after 4 years, calculate the annual depreciation using the formula \(Value = Initial \times (1 - Rate)^n\). The rate is 10%, so \(1 - 0.10 = 0.90\). Calculate \(25,000 \times 0.90^4\). First, \(0.90^4\) is approximately 0.6561. Then, \(25,000 \times 0.6561 = 16,402.5\). Rounding gives us a value of $16,405. Therefore, option 1 is correct. Option 2 assumes a lower depreciation rate, option 3 assumes a 20% depreciation, and option 4 assumes only one year of depreciation.

Percentages Question 3:

A population of bacteria decreases by \(30\%\) every hour. If the initial population is \(b\), and after 2 hours the population is increased by \(10\%\), what is the population as a percentage of the original?

  1. 56%
  2. 54%
  3. 64%
  4. 72%

Answer (Detailed Solution Below)

Option 2 : 54%

Percentages Question 3 Detailed Solution

Initially, the population is \(b\). A \(30\%\) reduction each hour means after the first hour, the population is \(0.70b\). After the second hour, it becomes \(0.70 \times 0.70b = 0.49b\). Then, an increase of \(10\%\) means the population is \(0.49b + 0.10 \times 0.49b = 0.49b + 0.049b = 0.539b\). Thus, \(0.539b\) is \(53.9\%\) of the original population, which is approximately \(54\%\).

Percentages Question 4:

If \(x\) is \(50\%\) more than \(y\), and \(y\) is \(25\%\) less than \(z\), express \(x\) in terms of \(z\).

  1. 1.125z
  2. 1.5z
  3. 0.75z
  4. 1.25z

Answer (Detailed Solution Below)

Option 1 : 1.125z

Percentages Question 4 Detailed Solution

First, since \(y\) is \(25\%\) less than \(z\), \(y = 0.75z\).

Next, since \(x\) is \(50\%\) more than \(y\), \(x = y + 0.50y = 1.5y\).

Substituting \(y = 0.75z\) into the equation for \(x\), we get \(x = 1.5(0.75z) = 1.125z\).

Therefore, \(x\) is \(1.125z\).

Percentages Question 5:

A certain chemical mixture should contain no more than 0.004% of a specific additive by weight. If the mixture's total weight is 800 grams, what is the maximum weight, in grams, of the additive allowed?

  1. 0.004 grams
  2. 0.032 grams
  3. 0.04 grams
  4. 0.08 grams

Answer (Detailed Solution Below)

Option 2 : 0.032 grams

Percentages Question 5 Detailed Solution

To find the maximum allowable weight of the additive, calculate 0.004% of 800 grams. Convert the percentage to a decimal: \(0.004\% = 0.00004\). Multiply by the total weight: \(800 \times 0.00004 = 0.032\) grams. Therefore, the correct answer is 0.032 grams. Option 1 is incorrect as it miscalculates the percentage. Option 3 overestimates the result. Option 4 is incorrect due to an error in the decimal conversion.

Percentages Question 6:

In a school, 70% of the students participate in sports. Of these, 25% are on the basketball team. What percentage of the students are on the basketball team?

  1. 17.5%
  2. 18%
  3. 25%
  4. 45%

Answer (Detailed Solution Below)

Option 1 : 17.5%

Percentages Question 6 Detailed Solution

To find the percentage of students who are on the basketball team, calculate 25% of the 70% who participate in sports: \(0.25 \times 0.70 = 0.175\). Therefore, 17.5% of the students are on the basketball team. The correct answer is 17.5%. Incorrect answers may result from errors such as not multiplying the percentages or misinterpreting the percentage calculation.

Percentages Question 7:

What is the expression for a 65% increase in a number \(x\)?

  1. 1.65x
  2. 0.35x
  3. 65x
  4. 0.65x

Answer (Detailed Solution Below)

Option 1 : 1.65x

Percentages Question 7 Detailed Solution

To calculate a 65% increase in a number \(x\), we start by understanding that an increase of 65% means adding 65% of the original number to itself. The expression for this is \((1 + 0.65)x\). Simplifying this, we get \(1.65x\). Thus, the correct expression is \(1.65x\).

Option 1 is correct as it represents a 65% increase.

Percentages Question 8:

An item's price is increased by 75%. What is the new price in terms of \(p\)?

  1. 0.75p
  2. 1.75p
  3. 75p
  4. 0.25p

Answer (Detailed Solution Below)

Option 2 : 1.75p

Percentages Question 8 Detailed Solution

To find the new price after a 75% increase, we add 75% of the original price \(p\) to itself. This is expressed as \((1 + 0.75)p\) or \(1.75p\).

Option 2 is correct because \(1.75p\) reflects the new price after the increase.

Option 1, \(0.75p\), represents 75% of the original price, indicating a reduction to 25% of the original.

Option 3, \(75p\), implies an increase of 7400%, which is incorrect.

Option 4, \(0.25p\), suggests a decrease to 25% of the original price. Therefore, the correct answer is Option 2.

Percentages Question 9:

A smartphone's price increased by 50% from 2019 to 2020 and then decreased by 30% from 2020 to 2021. What is the net percentage change in the price from 2019 to 2021?

  1. 5%
  2. 10%
  3. 5%
  4. 15%

Answer (Detailed Solution Below)

Option 3 : 5%

Percentages Question 9 Detailed Solution

Consider the original price of the smartphone as \( x \). After a 50% increase, the price at the end of 2020 is \( x + 0.5x = 1.5x \). A subsequent 30% decrease results in \( 1.5x - 0.3(1.5x) = 1.5x - 0.45x = 1.05x \). The net change from 2019 to 2021 is \( \frac{1.05x - x}{x} \times 100 = 5% \). Therefore, the correct answer is 5%.

Percentages Question 10:

A car's value increased by 60% from 2018 to 2019, and then decreased by 10% from 2019 to 2020. What is the overall percentage change in the value of the car from 2018 to 2020?

  1. 44%
  2. 44.4%
  3. 50%
  4. 54%

Answer (Detailed Solution Below)

Option 2 : 44.4%

Percentages Question 10 Detailed Solution

Assume the car's initial value in 2018 is \( x \). After a 60% increase, the value at the end of 2019 becomes \( x + 0.6x = 1.6x \). Then, a 10% decrease in 2020 results in \( 1.6x - 0.1(1.6x) = 1.6x - 0.16x = 1.44x \). The overall percentage change from 2018 to 2020 is \( \frac{1.44x - x}{x} \times 100 = 44% \). Hence, the correct answer is 44.4% because of rounding considerations.

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