Frequency Modulation MCQ Quiz in తెలుగు - Objective Question with Answer for Frequency Modulation - ముఫ్త్ [PDF] డౌన్లోడ్ కరెన్
Last updated on Mar 9, 2025
Latest Frequency Modulation MCQ Objective Questions
Top Frequency Modulation MCQ Objective Questions
Frequency Modulation Question 1:
Which of the following is NOT the advantage of frequency modulation ?
Answer (Detailed Solution Below)
Frequency Modulation Question 1 Detailed Solution
Concept:
Modulation: The process of varying some characteristics such as amplitude, frequency, or phase of a carrier signal is varied in accordance with the instantaneous value of the low-frequency audio signal(or modulating signal) is known as Modulation. In other words, in modulation, we use a high-frequency carrier wave to carry audio signals(message) to large distances. Audio signals have low frequencies with a bandwidth of about 20 kHz only. Such low signals cannot be transmitted directly to large distances. That is why we need modulation of these audio signals.
Frequency Modulation: The process of changing the frequency of a message signal in accordance with the amplitude of a modulating signal voltage is known as Frequency modulation. The frequency of modulated signal increases as the amplitude of modulating signal increases and decreases as the amplitude of modulating signal decreases. Some other features of Frequency modulation are-
- The amplitude of the message signal does not change in FM.
- The amount of frequency deviation is proportional to the amplitude of instantaneous value of modulating signal.
- FM transmission is highly efficient.
Advantages of FM:
- It is highly efficient.
- Noise interference is low.
- High fidelity reception.
Disadvantages of FM:
- A wider channel is required for FM.
- Components are costly.
- It is limited to line of sight.
Explanation:
FM is very efficient, produces less noise, and all the power transmitted is useful. So maximum power transmitted is useful. All these are the advantages of FM. But the receivers and transmitters are very complex and costly.
The correct answer is option (4)Additional Information
Frequency Deviation: The amount by which the frequency of carrier signal shifts above or below the resting frequency fc is called the frequency deviation.
Frequency Modulation Question 2:
Determine the bandwidth required for an FM signal having frequency 2 kHz and maximum deviation 10 kHz.
Answer (Detailed Solution Below)
Frequency Modulation Question 2 Detailed Solution
Concept:
According to Carson rule signal, BW is given as:
B.W = (β + 1) 2fm
\(\becauseβ=\frac{Δf}{f_m} \)
B.W. = 2[Δf + fm]
If multiple frequencies are available in modulating signal then,
B.W. = 2(β + 1) fmax
Calculation:
Given:
Δf = 10 kHz
fm = 2 kHz
B.W. = 2[Δf + fm]
B.W. = 2(10 + 2)
BW = 24 kHz
Hence option (3) is the correct answer.
Frequency Modulation Question 3:
In FM modulation, when the modulation index increases, the transmitted power is
Answer (Detailed Solution Below)
Frequency Modulation Question 3 Detailed Solution
Analysis:
The amplitude Ac is constant in a phase-modulated or a frequency modulated signal. RF power does not depend upon the modulation index.
A general expression for a phase or frequency modulated signal is:
\(\phi(t)=A_ccos[ω_ct+g(k_k,m(t))]\)
m(t) = the modulating signal
ωc = Carrier frequency
kk becomes kc for FM and kp for PM.
The average power (Pavg) is given by:
\(P_{avg}=\frac{A_c^2}{2}\) (Always)
We observe that the transmitted power is independent of the modulation index in case of FM.
Transmitted power in AM is given by:
\({P_t} = {P_c}\left( {1 + \frac{{{\mu ^2}}}{2}} \right)\)
Pc = Carrier Power
∴ We conclude that If the modulation index increases, transmitted power increases in case of AM and is unchanged for FM.
Frequency Modulation Question 4:
What is the modulation index in a frequency modulated signal with a carrier frequency of 100 kHz, modulating frequency of 4 kHz and frequency deviation of 50 kHz?
Answer (Detailed Solution Below)
Frequency Modulation Question 4 Detailed Solution
Concept:
In FM (Frequency Modulation), the modulation index is defined as the ratio of frequency deviation to the modulating frequency.
Mathematically, this is defined as:
\(m_f=\frac{Δ f}{f_m}\)
mf = Modulation index
Δf = Frequency deviation
fm = Modulating frequency
Calculation:
Given Δf = 50 kHz
fm = 4 kHz
\(m_f=\frac{50~kHz}{4~kHz}=12.5\)
A wave has 3 parameters Amplitude, Phase, and Frequency. Thus there are 3 types of modulation techniques.
Amplitude Modulation: The amplitude of the carrier is varied according to the amplitude of the message signal.
Frequency Modulation: The frequency of the carrier is varied according to the amplitude of the message signal.
Phase Modulation: The Phase of the carrier is varied according to the amplitude of the message signal.
Frequency Modulation Question 5:
Which of the following is the advantage of AM over FM?
Answer (Detailed Solution Below)
Frequency Modulation Question 5 Detailed Solution
Advantages of FM over AM are:
- Improved signal to noise ratio (about 25dB) w.r.t. to manmade interference.
- Smaller geographical interference between neighboring stations.
- Less radiated power.
- Well-defined service areas for given transmitter power.
Disadvantages of FM:
- Much more Bandwidth (as much as 20 times as much).
- More complicated receiver and transmitter.
Frequency Modulation Question 6:
The range of frequency generated by VHF oscillator is -
Answer (Detailed Solution Below)
Frequency Modulation Question 6 Detailed Solution
Explanation:
Very High Frequency:
It has a range of 30 MHz to 300 MHz and are used in television broadcast.
Some ultra high frequencies are also used in television broadcasting.
Additional Information
The frequency spectrum for the complete range is:
Name |
Frequency Range |
Very low frequency (VLF) |
0.003 MHz – 0.03 MHz |
Low frequency (LF) |
0.03 MHz – 0.3 MHz |
Medium frequency (MF) |
0.3 MHz – 3 MHz |
High frequency (HF) |
3 MHz – 30 MHz |
Very High frequency (VHF) |
30 MHz – 300 MHz |
Ultra-High Frequency (UHF) |
300 MHz – 3000 MHz |
Super High Frequency (SHF) |
3000 MHz – 30,000 MHz |
Extra-High Frequency (EHF) |
30,000 MHz – 3,00,000 MHz |
Hence option (3) is the correct answer.
Frequency Modulation Question 7:
In television, video and sound signal are respectively
Answer (Detailed Solution Below)
Frequency Modulation Question 7 Detailed Solution
In TV Transmission FM is used for sound transmission and AM for video/picture transmission.
Amplitude Modulation (AM) is preferred for picture transmission in TV because of the following reasons:
- The distortion which arises due to interference between multiple signals is more in FM than AM because the frequency of the FM signal continuously changes. Steady production of the picture is affected because of this.
- If AM were used, the ghost image, if produced is steady.
- Also, the circuit complexity and bandwidth requirements are much less in AM than in FM.
On the other hand, FM is preferred for sound because of the following reasons:
- The bandwidth assigned to the FM sound signal is about 200 kHz, of which not more than 100 kHz is occupied by significant sidebands.
- This is only 1.4 % of the total channel bandwidth of 7 MHz. This results in efficient utilization of the channel.
Important Notes:
Amplitude Modulation: The amplitude of the carrier is varied according to the amplitude of the message signal.
Frequency Modulation: The frequency of the carrier is varied according to the amplitude of the message signal.
Phase Modulation: The Phase of the carrier is varied according to the amplitude of the message signal.
Frequency Modulation Question 8:
The four basic elements in a PLL are loop filter, loop amplifier, VCO and
Answer (Detailed Solution Below)
Frequency Modulation Question 8 Detailed Solution
- A phase-locked loop is a control system that generates an output signal whose phase is related to the phase of an input signal.
- The circuit can track an input frequency or it can generate a frequency that is a multiple of the input frequency.
- The basic elements of a PLL circuit are phase comparator/detector, a loop filter, voltage controlled oscillator (VCO).
The figure shows a schematic of a phase-locked loop:
Frequency Modulation Question 9:
FM signal is better than AM signal because ______?
Answer (Detailed Solution Below)
Frequency Modulation Question 9 Detailed Solution
Features |
AM |
FM |
Noise immunity |
In AM, the message is stored in the form of variation in amplitude. Noise affects the amplitude of signal most so AM is less noise immune. |
In FM, the message is stored in the form of variation in frequency so it has better noise immunity. |
Bandwidth |
B.W. required in AM is = 2fm. Hence, less bandwidth is required in case of AM. |
B.W. required in FM is = 2(β+1)fm. Hence, more bandwidth is required in case of FM. |
Transmitted power |
Power transmitted in AM is given by: \({P_T} = {P_c}\left( {1 + \frac{{{\mu ^2}}}{2}} \right)\) As the modulation index ‘μ’ increases power in AM increases. |
In FM, power transmitted is always equal to the total power of carrier before modulation. Hence, FM requires less power than AM. |
Frequency Modulation Question 10:
In a modulation system, the modulating voltage remains the same, the modulation index is halved when the modulating frequency is doubled, the system is
Answer (Detailed Solution Below)
Frequency Modulation Question 10 Detailed Solution
Concept:
Modulation Index (β) in FM is given by:
\(\beta = \frac{{Frequency\;deviation}}{{Message\;frequency}} = \frac{{{k_f}{A_m}}}{{{f_m}}}\)
kf = frequency sensitivity
Am = modulating voltage
Application:
Given:
fm = 2 fm, Am’ = Am
So,
\(\beta ' = \frac{{{k_f}A_m'}}{{f_m'}} = \frac{{{k_f}{A_m}}}{{2{f_m}}}\)
∴ We can write:
\(\beta ' = \frac{\beta }{2}\)
Hence, the given modulating system is FM.
Note:
In AM modulation Index is defined as:
\(\mu = \frac{{{A_m}}}{{{A_c}}} = \frac{{{A_{max}} - {A_{min}}}}{{{A_{max}} + {A_{min}}}}\)
Clearly, it is independent of fm.
∴ it will not fulfill the given criteria.
In PM, the modulation index is defined as:
β = kp Am
kp = phase sensitivity
It will also not fulfill the given criteria.