IC Engine Cycles MCQ Quiz in తెలుగు - Objective Question with Answer for IC Engine Cycles - ముఫ్త్ [PDF] డౌన్‌లోడ్ కరెన్

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పొందండి IC Engine Cycles సమాధానాలు మరియు వివరణాత్మక పరిష్కారాలతో బహుళ ఎంపిక ప్రశ్నలు (MCQ క్విజ్). వీటిని ఉచితంగా డౌన్‌లోడ్ చేసుకోండి IC Engine Cycles MCQ క్విజ్ Pdf మరియు బ్యాంకింగ్, SSC, రైల్వే, UPSC, స్టేట్ PSC వంటి మీ రాబోయే పరీక్షల కోసం సిద్ధం చేయండి.

Latest IC Engine Cycles MCQ Objective Questions

Top IC Engine Cycles MCQ Objective Questions

IC Engine Cycles Question 1:

In an Otto cycle, the compression ratio is 9:1 and the pressure and temperature at the beginning of the compression process are 100 kPa and 10°C. The heat addition by combustion gives the highest temperature as 2500 K. Specific heat added by combustion is:

  1. 0.762 MJ/kg
  2. 1.305 MJ/kg
  3. 0.286 MJ/kg
  4. 1.048 MJ/kg

Answer (Detailed Solution Below)

Option 2 : 1.305 MJ/kg

IC Engine Cycles Question 1 Detailed Solution

Concept:

\(\frac{{{T_2}}}{{{T_1}}} = {\left( {\frac{{{V1}}}{{{V_2}}}} \right)^{\gamma - 1}}\)

Q23 = m × Cv × (T3 – T2)

T = temperature (K)

V = volume (m3)

Q23 = specific heat added by combustion

Cv = specific heat at constant volume (kJ/kg.K)

Calculation:

Given:

SSC JE Mechanical 15 10Q 25th Jan Morning Part 4 Hindi - Final images Q3d

P1 = 100 kPa

T1 = 10°C = 10 + 273 = 283 K

\(\frac{{{V_1}}}{{{V_2}}} = 9\)

\({\gamma} = 1.4 \)

Process 1 – 2 → isentropic compression

\(\frac{{{T_2}}}{{{T_1}}} = {\left( {\frac{{{V1}}}{{{V_2}}}} \right)^{\gamma - 1}}\)

T2 = 283 × (9)1.4 – 1 = 681.52 K

Process 2 – 3 → heat addition at constant volume

Q23 = m × Cv × (T3 – T2)

Cv = 718 J/kg.K

Q23 = 718 (2500 – 681.52)

Q23 = 1.305 × 106 J/kg

Q23 = 1.305 MJ/kg

IC Engine Cycles Question 2:

The pressure at the end of compression in the case of diesel engine is of the order of

  1. 35 kg/cm2
  2. 6 kg/cm2
  3. 12 kg/cm2
  4. 20 kg/cm2

Answer (Detailed Solution Below)

Option 1 : 35 kg/cm2

IC Engine Cycles Question 2 Detailed Solution

Explanation:

SI engine CI engine
Petrol is used as fuel. Diesel is used as fuel.
A petrol engine draws a mixture of petrol and air during the suction stroke. A diesel engine draws only air during the suction stroke.
The pressure at the end of the compression is about 10 kg/cm2. The pressure at the end of the compression is about 35 kg/cm2.
The charge (i.e. petrol and air mixture) is ignited with the help of spark plug. The fuel is injected in the form of a fine spray. The temperature of the compressed air is about 600° C at a pressure of about 35 bars.
A  carburettor is used to atomize, vaporize and meter the correct amount of fuel according to the requirement. Fuel injection pumps and atomizers are used to inject metered quantities of fuel at high pressure according to the requirement.
A petrol engine has a compression ratio approximately from 6 to 10. A diesel engine has a compression ratio of approximately 15 to 25.
The combustion of fuel takes place approximately at a constant volume. In other words, it works on the Otto cycle. The combustion of fuel takes place approximately at constant pressure. in other words, it works on the Diesel cycle.
Less vibration, and hence, smooth running. More vibration, and hence, rough running and noisier.
Engine weight is less. Engine weight is more.
It emits carbon monoxide. (CO) It emits carbon dioxide. (CO2)

IC Engine Cycles Question 3:

The ratio of brake power output to the fuel energy input per unit time is called:

  1. Volumetric efficiency
  2. Thermal efficiency
  3. Mechanical efficiency
  4. Relative efficiency

Answer (Detailed Solution Below)

Option 2 : Thermal efficiency

IC Engine Cycles Question 3 Detailed Solution

Concept:

Brake Thermal efficiency:

It is defined as the ratio of brake power to the fuel energy per unit time.

\(Brake\;thermal\;efficiency\left( {{η _b}} \right) = \frac{{BP}}{{{m_f} \times CV}} = \frac{1}{{BSFC \times CV}}\)

where mf = mass flow rate of fuel, BP = Brake Power, CV = Calorific Value.

26 June 1

Indicated power:

The energy of the fuel that is converted to power is called the indicated power (I.P).

Friction power:

The energy applied to the piston passes through the connecting rod to the crankshaft. In the transmission, there are energy losses due to friction, pumping, etc. The sum of all there losses converted to power is termed as friction power(F.P).

Brake power:

Brake power(B.P) = Indicated power (I.P) - Friction Power (F.P)

Volumetric efficiency (η):

Volumetric efficiency is defined as the ratio of actual volume flow rate of air into the system to the rate at which the volume is displaced by the system.

\(Volumetric\;efficiency = \frac{{Actual ~intake\;volume}}{{Swept\;volume}}\)

Mechanical efficiency:

\({\eta _{mech}} = \frac{{brake\;power}}{{indicated\;power}}\)

IC Engine Cycles Question 4:

Cp and Cv for working fluid in a diesel cycle are 1 kJ/kgK and 0.718 kJ/kgK respectively. Temperatures at the beginning and the end of the heat addition process are 1473 K and 1723 K respectively. The heat added is:

  1. 179.5 kJ/kg
  2. 250 kJ/kg
  3. 420 kJ/s
  4. 430.75 kJ/kg

Answer (Detailed Solution Below)

Option 2 : 250 kJ/kg

IC Engine Cycles Question 4 Detailed Solution

Concept:

Gate ME 2017 IC Application Images-Q4

Heat addition in the diesel cycle is a constant pressure process.

Heat added (Q) = Cp × (T­3 – T2) kJ/kg

Cp = Heat capacity at the constant process.

T2 = Temperature at the end of the heat addition process

T2 = Temperature at the beginning of the heat addition process

Calculation:

Given:

Cp = 1 kJ/kgk, T3 = 1723 K, T2 = 1473 K

Q = 1 × (1723 - 1473) = 250 kJ/kg

IC Engine Cycles Question 5:

In SI engines for higher thermal efficiency

  1. Compression ratio should be high
  2. Heat liberation during combustion should be maximum
  3. Surface to volume ratio should be high
  4. Long flame travel distance

Answer (Detailed Solution Below)

Option 1 : Compression ratio should be high

IC Engine Cycles Question 5 Detailed Solution

Explanation:

RRB JE ME 49 15Q TE CH 4 HIndi - Final Diag(Shashi) images Q4

The thermal efficiency of the Otto Cycle:

\({\eta _{otto}} = 1 - \frac{1}{{{r^{\gamma - 1}}}}\)

Compression ratio: r = v1/v2

Conclusion:

\(\eta = f\left( {r,\gamma } \right)\)

From the above equation, it can be observed that the efficiency of the Otto cycle is mainly the function of compression ratio for the given ratio of Cp and Ci.e. ratio of specific heats.

The thermal efficiency of the theoretical Otto cycle increases with an increase in compression ratio and specific heat ratio but is independent of the heat added (independent of load).

RRB JE ME 49 15Q TE CH 4 HIndi - Final Diag(Shashi) images Q4a

The efficiency of the Otto cycle is given by

\({\eta _{Otto}} = 1 - \frac{1}{{{r^{\gamma - 1}}}}\)

As \(r \uparrow ,\left( {\frac{1}{{{r^{\gamma - 1}}}}} \right) \downarrow \) and Hence \({\eta _{Otto}} \uparrow\).

Option (b), (c) and (d) are the knock parameters.

IC Engine Cycles Question 6:

Otto cycle consists of following four processes 

  1. Two isothermals and two isentropic
  2. Two isentropic and two constant volumes
  3. Two isentropic, one constant volume and one constant pressure
  4. Two isentropic and two constant pressures

Answer (Detailed Solution Below)

Option 2 : Two isentropic and two constant volumes

IC Engine Cycles Question 6 Detailed Solution

Explanation:

Otto cycle:

The air-standard-Otto cycle is the idealized cycle for the spark-ignition internal combustion engines.

Otto cycle is the one which has two constant volume heat transfer processes and two adiabatic work transfer processes.

The Otto cycle 1-2-3-4 consists of the following four processes:

  • Process 1-2: Reversible adiabatic compression of air
  • Process 2-3: Heat addition at constant volume
  • Process 3-4: Reversible adiabatic expansion of air
  • Process 4-1: Heat rejection at constant volume
     

RRB JE ME 49 15Q TE CH 4 HIndi - Final Diag(Shashi) images Q14d

  • During constant volume process heat addition and heat, rejection takes place and no work transfer.
  • During the adiabatic processes [compressions/expansion] only work transfer taken place but no heat transfer occurs.

Important Points

Otto  Cycle     
  • Constant volume heat addition.
  • Constant volume heat rejection.
Carnot Cycle   
  • Constant temperature heat addition
  • Constant temperature heat rejection
Diesel Cycle 
  • Constant pressure heat addition.
  • Constant volume heat rejection.
Dual Cycle 
  • Constant volume and constant pressure heat addition.
  • Constant volume heat rejection

IC Engine Cycles Question 7:

The relation between compression ratio(r), cut-off ratio(rc) and expansion ratio(re) of a diesel cycle is given by

  1. rc × r = re
  2. r × re = rc
  3. rc × re = r
  4. no such specific relation

Answer (Detailed Solution Below)

Option 3 : rc × re = r

IC Engine Cycles Question 7 Detailed Solution

Concept:

For the Diesel cycle:

IC engines Part 2 images Q3a

Processes involved in compression engine (diesel cycle) are:

1-2: Reversible adiabatic compression

2-3: Constant pressure heat addition

3-4: Reversible adiabatic expansion

4-1: Constant volume of heat rejection

Now 

The compression ratio is given by

\(r = \frac{{{V_1}}}{{{V_2}}}\)

The cut-off ratio is given by

\(r_c = \frac{{{V_3}}}{{{V_2}}}\)

The expansion ratio is given by 

\(r_e = \frac{{{V_4}}}{{{V_3}}}\)

⇒ rc × re = \(\frac{V_4}{V_2}\) = \(\frac{V_1}{V_2}\) = r   (From diagram V4 = V1)

IC Engine Cycles Question 8:

The efficiency of an Otto cycle is 60% and ratio of specific heats is 1.5. What is the compression ratio?

  1. 2.25
  2. 4
  3. 6.25
  4. 8

Answer (Detailed Solution Below)

Option 3 : 6.25

IC Engine Cycles Question 8 Detailed Solution

Concept:

P-V and T-S diagram of Otto cycle is shown in the figure.

06.05.2018.012

Compression Ratio (r) is the ratio of the total cylinder volume when the piston is at the bottom bead centre, VT, to the clearance volume VC.

\(r = \frac{{{V_T}}}{{{V_C}}} = \frac{{{V_c} + {V_s}}}{{{V_c}}} = 1 + \frac{{{V_s}}}{{{V_c}}}\)

\({η _{Otto}} = 1 - \frac{1}{{{r^{γ - 1}}}}\)

Calculation:

Given:

η = 60%, γ = 1.5

\(\begin{array}{l} {η _{Otto}} = 1 - \frac{1}{{{{\left( r \right)}^{γ - 1}}}}\\ 0.6 = 1 - \frac{1}{{{{\left( r \right)}^{1.5 - 1}}}}\\ \frac{1}{{{{\left( r \right)}^{0.5}}}} = 0.4 \Rightarrow r = 6.25 \end{array}\) 

IC Engine Cycles Question 9:

In a diesel engine, the suction contains- 

  1. Fuel Only
  2. Air Only
  3. Air or Fuel 
  4. Mixture of air and Fuel

Answer (Detailed Solution Below)

Option 2 : Air Only

IC Engine Cycles Question 9 Detailed Solution

Explanation:

The difference between Petrol and diesel engine are:

Petrol engine Diesel engine
Petrol is used as fuel. Diesel is used as fuel.
A petrol engine draws a mixture of petrol and air during the suction stroke. A diesel engine draws only air during the suction stroke.
The pressure at the end of the compression is about 10 bar. The pressure at the end of the compression is about 35 bar.
The charge (i.e. petrol and air mixture) is ignited with the help of a spark plug. The fuel is injected in the form of a fine spray. The temperature of the compressed air is about 600°C at a pressure of about 35 bars.
A  carburettor is used to atomize, vaporize and meter the correct amount of fuel according to the requirement. Fuel injection pumps and atomizers are used to inject metered quantities of fuel at high pressure according to the requirement.
A petrol engine has a compression ratio of approximately 6 to 10. A diesel engine has a compression ratio of approximately 15 to 25.
The combustion of fuel takes place approximately at a constant volume. In other words, it works on the Otto cycle. The combustion of fuel takes place approximately at constant pressure. in other words, it works on the Diesel cycle.
Less vibration, and hence, smooth running. More vibration, and hence, rough running and noisier.
Engine weight is less. Engine weight is more.
It emits carbon monoxide. (CO) It emits carbon dioxide. (CO2)

F1 Ashiq 22.1.21 Pallavi D1.1  F1 Ashiq 22.1.21 Pallavi D2

Additional Information

Flywheel

  • A flywheel is an inertial energy-storage device. It absorbs mechanical energy and serves as a reservoir, storing energy during the period when the supply of energy is more than the requirement and releases it during the period when the requirement of energy is more than the supply.
  • Diesel engines have a higher compression ratio, temperature, pressure, size and weight than a petrol engine.
  • The weight of the flywheel depends upon the nature of the variation of the pressure.
  • The flywheel for a diesel engine is bigger than that of a petrol engine.​


Gudgeon pins

  • The gudgeon pins are made of nickel/chromium alloy steel.
  • The outer surface is ground, chromium-plated, and case hardened.
  • The gudgeon pin connects the piston with the connecting rod.
  • It should be strong enough to transmit power and withstand the pressure of combustion.
  • They are made hollow to reduce the inertia load due to reciprocating motion.
  • It is present in both petrol and diesel engine.


Piston rings: 

Piston rings are expandable split rings embedded inside the grooves on the perimeter of a piston and mainly perform the following functions-

  • Seal the combustion chamber from the crankcase
  • Provide a uniform oil film between the piston and cylinder wall thereby controlling the oil consumption
  • Transfer the heat from the piston to the cool cylinder walls.
    • In most cases, piston rings are made up of Cast Iron
    • Cast iron easily adheres to the cylinder wall
    • In addition, cast iron can be easily coated with other materials to enhance its durability
  • There are two types of piston rings
    • Compression rings
    • Oil control rings

IC Engine Cycles Question 10:

Most high-speed compression engines operate on

  1. Otto cycle
  2. Diesel cycle
  3. Dual cycle
  4. Carnot cycle

Answer (Detailed Solution Below)

Option 3 : Dual cycle

IC Engine Cycles Question 10 Detailed Solution

Concept:

  • A dual cycle or limited pressure cycle is a thermodynamic cycle for high-speed diesel and hot spot ignition engines.
  • Whether heat is added at constant pressure or constant volume in actual applications, depends upon the rate of heat added and the rate at which pressure decreases due to movement of the piston.
  • In an ideal cycle, the piston is assumed stationary during heat addition at constant volume, but in practice, this does not happen.
  • As the speed of the engine increases, the rate of decrease of pressure due to the movement of the piston increases, and heat addition cannot be assumed at either constant volume or constant pressure.
  • In such a case, a better approach for modeling the situation will be to assume heat addition initially at constant volume and then at constant pressure. That is why a dual combustion cycle is used.

SSC JE Mechanical 15 10Q 25th Jan Morning Part 4 Hindi - Final images Q1

  • All diesel engines except slow-speed engines use mixed dual cycles.
  • This is because in mixed dual cycles the heat input occurs partially at constant volume and partially at constant pressure.
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