Question
Download Solution PDFA certain item of raw food contains 35% starch, 25% protein, the rest fibre. The item is cooked by boiling in water, which doubles its weight. Half of the fibre in the food becomes soluble when cooked. If the cooked item weighs 200 g, the amount of soluble fibre in it is
Answer (Detailed Solution Below)
Option 3 : 20 g
Detailed Solution
Download Solution PDFThe correct answer is 20 g
Explanation:
Let the initial weight of the raw food be x grams.
After cooking, the weight of the food becomes 2x grams.
Given that the cooked item weighs 200 g, we have:
2x = 200 g
⇒ x = 100 g
Amount of fibre in raw food = 100 - (35 + 25) = 40% of 100 g = 40 g
Half of the fibre becomes soluble when cooked:
Soluble fibre = 40 g / 2 = 20 g
Therefore, the amount of soluble fibre in the cooked item is 20 g.