Question
Download Solution PDFA coil having 100 turns is placed in the magnetic field of 1m wb. Find the average EMF induced if the coil is moved in 0.2 seconds from the given field to a field of 0.4m wb.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The magnitude of the induced EMF in a coil is given by:
\(E=N{dϕ\over dt}\)
\(E=N\times ({ϕ_2-ϕ_1\over t_2-t_1})\)
where, N = No. of turns
ϕ = Flux in Weber
t = Time in sec
Calculation
Given, N = 100
\(E=100\times ({1-0.4\over 0.2-0})\times 10^{-3}\)
E = 0.3 volt
Last updated on Jun 16, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.