Question
Download Solution PDFA coil of 100 turns is wound on a magnetic circuit of reluctance 1000 AT/mWb. The current of 1A flowing in the coil is reversed in 10 ms. The average EMF induced in the coil is ________ V.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The average EMF induced in the coil is given by:
\(E=-N{Δ ϕ \over Δ t}\)
The magnetic flux is given by:
\(ϕ = {NI\over R}\)
where, E = EMF
N = No. of turns
Δϕ = Change in flux
Δt = Change in time
I = Current
R = Reluctance
Calculation
Given, N = 100
I = 1 A
R = 1000 AT/Wb
When the current reverses, the flux changes from Wb to Wb.
The change in flux is given by:
Δϕ = ϕfinal - ϕinitial
Δϕ = (−0.1) − (0.1) = −0.2 Wb
\(E=-(100)× {-0.2 \over 10× 10^{-3}}\)
E = 100 × 20 × 10-3 V
E = 2 V
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