A spur gear has module 2 mm and 30 number of teeth rotating at 200 rpm. What will be its circular pitch in mm?

Question

Question

This question was previously asked in

MPPGCL JE ME 19 March 2019 Official Paper

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Answer 1

Concept:

Pitch line velocity,

VP \(= {\rm{\omega }}.r = \frac{{2π N}}{{60}} × \frac{d}{2}\)

\(V_P= \frac{{2π N}}{{60}} × \frac{{mT}}{2}\;\;\;\;\;\;\;\left( {as\;m = \frac{d}{T}} \right)\)

Circular pitch,

p = π m

Calculation:

Given:

No of teeth (T) = 30

module (m) = 2 mm

speed (N) = 200 rpm

p = π × 2

p = 6.28 mm