Question
Download Solution PDFA voltage has a true value of 1.5 V analog indicating instrument with a range of 0 - 2.5 V shows a voltage 1.46 V. The relative error is :
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Absolute error: The magnitude of the difference between the measurement of the experimental readings and the true value of the quantity is called the absolute error.
- This is denoted by |Δa |.
- While calculating the measurements, in absence of the true value, we consider the arithmetic mean of the measurements as the true value.
- absolute error is always constant.
-
Δa = measured value - true value
Relative error: It is the ratio of mean absolute error to mean value of the quantity measured while performing the measurement.
- It is also known as fractional error.
- relative error is always expressed in percentage.
- relative error = \(\frac{Δa }{true\ value}\) × 100
- relative error in terms of FSD(full scale deflection)= \(\frac{Δa}{FSD}\) × 100
Calculation:
FSD = 2.5V
true value = 1.5 V
measured value is 1.46 V
Δa = 1.46 - 1.5 = - 0.04
relative error = \( \frac {-0.04} {1.5}\) × 100
= -2.67%
so correct option is 2.
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