Question
Download Solution PDFFive observers have taken a set of independent voltage measurements and recorded as 110.10 V, 110.20 V, 110.15 V, 110.30 V and 110.25 V. Under the situation mentioned above, the range of error is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFRange of error:
= ± |Exterme reading - Average reading|
Average reading
\(\frac{{110.10{\rm{ }}V + 110.20{\rm{ }}V + {\rm{ }}110.15{\rm{ }}V + 110.30{\rm{ }}V + {\rm{ }}110.25{\rm{ }}V}}{5}\)
= 110.20
Range of error
= ± |110.30 - 110.20|
= ± 0.10
Alternate method:
\(RE = ±\frac{{Max - Min}}{2}\)
\(RE = ±\frac{{110.30 - 110.10}}{2}\)
= ± 0.1
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