A woman is standing 30 m away from her house. An angle of elevation from the top of her is 30° towards the top of house and angle of elevation from her foot is 60° towards the top of the house. Find the total height of the house and woman.

  1. 20 m
  2. 50√3 m
  3. 20√3 m
  4. 10√3 m

Answer (Detailed Solution Below)

Option 2 : 50√3 m
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Detailed Solution

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Given:

A woman is standing 30 m away from her house. An angle of elevation from the top of her is 30° towards the top of house and angle of elevation from her foot is 60° towards the top of the house

SSC 31Q images Q26

Calculation:

In ΔABC,

⇒ tan30° = AB/BC

⇒ 1/√3 = AB/30 

⇒ AB = 30/√3

⇒ AB = 30√3/(√3 × √3) 

⇒ AB = 10√3 m

In ΔAED,

⇒ tan60° = AE/ED

⇒ √3 = (AB + BE)/30

⇒ AB + BE = 30√3

⇒ BE = 30√3 – 10√3

⇒ BE = 20√3 m

Total height of the house = 10√3 + 20√3 = 30√3

Height of the women = CD = BE = 20√3

Total height of the house and women = 30√3 + 20√3 = 50√3

∴ Total height of the house and women is 50√3 

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