Question
Download Solution PDFएक महिला आपल्या घरापासून 30 मीटर अंतरावर उभी आहे. तिच्या शीर्षस्थानापासून घराच्या शिखरावर उन्नतांश कोन 30° आहे आणि तिच्या पायापासून घराच्या शिखराला उन्नतांश कोन 60° आहे. घर आणि स्त्रीची एकूण उंची शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिल्याप्रमाणे,
ΔABC मध्ये,
⇒ tan30° = AB/BC
⇒ 1/√3 = AB/30
⇒ AB = 30/√3
⇒ AB = 30√3/(√3 × √3)
⇒ AB = 10√3 मी
ΔAED मध्ये,
⇒ tan60° = AE/ED
⇒ √3 = (AB + BE)/30
⇒ AB + BE = 30√3
⇒ BE = 30√3 – 10√3
⇒ BE = 20√3 मी
घराची एकूण उंची = 10√3 + 20√3 = 30√3
स्त्रीची उंची = CD = BE = 20√3
घराची आणि स्त्रीची एकूण उंची = 30√3 + 20√3 = 50√3
∴ घराची आणि स्त्रीची एकूण उंची 50√3 आहे.
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