Question
Download Solution PDFAs per IRC, the minimum length of transition curve for a mountainous terrain road with radius of curvature 100 m and design speed of vehicle 100 kmph is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Length of transition curve
Based on IRC Formula
\({l_s} = \frac{{{V^2}}}{R}\) for Hilly terrain and \({l_s} = \frac{{2.7{V^2}}}{R}\) for Plain and Rolling terrain.
Where
Ls = length of the transition curve (m), V = speed of the vehicle (km/hour),
R = radius of the transition (m),
Calculation:
Given,
Design Speed = 100 kmph, Radius (R) = 100 m
iii) By empirical formula
For Mountainous or Hilly Terrain
\({\rm{V}} = \frac{{{{\rm{V}}^2}}}{{\rm{R}}} = \frac{{ {{100}^2}}}{{100}} = 100{\rm{\;m}}\)
∴ The length of the transition curve-based IRC empirical formula is 100 m
Additional InformationLength of transition curve (Maximum value is to be considered among the below options)
a) Based on the rate of change of centrifugal acceleration (c)
\({{\rm{l}}_{\rm{s}}} = \frac{{{v^3}}}{{c \times R}}\)
where \(c = \frac{{80}}{{75 + V}}\) ……….. c value should be between 0.5 to 0.8
b) Based on the rate of change of superelevation (e)
1. Superelevation attained by rotation about the inner edge or outer edge
\({l_s} = eN\left( {w + w \times e} \right)\)
2. Superelevation attained by rotation about the center
\({l_s} = \frac{{eN\left( {w + w \times e} \right)}}{2}\)
c) Based on IRC Formula
\({l_s} = \frac{{{V^2}}}{R}\) for Hilly terrain and \({l_s} = \frac{{2.7{V^2}}}{R}\) for Plain and Rolling terrain.
Where
Ls = length of the transition curve (m), v = speed of the vehicle (m/s), V = speed of the vehicle (km/hour),
e = required superelevation, N = rate of change of superelevation to be attained, R = radius of the transition (m), and
w = width of road/pavement
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