Question
Download Solution PDFএকটি বৃত্তের ব্যাসার্ধ 10 সেমি। PQ এবং PR হল বৃত্তের দুটি স্পর্শক এবং ∠QOR = 120 °, তাহলে, (PQ + PR + QR) এর মান কত?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত,
∠QOR = 120°
অতএব, ∠QOP = ∠ROP = 60°
∠OQP = ∠ORP = 90°
⇒ ∠QPO = ∠RPO = 30°
OQ = OR = 10 সেমি
∴
⇒
⇒ 1/2 = 10/OP
⇒ OP = 20 সেমি
∴
⇒
⇒
∴
আমরা জানি ΔOQP ত্রিভুজের ক্ষেত্রফল =
⇒
⇒
⇒
∴ QR = 2 × KQ = 2 × 5√3 = 10√3 সেমি
প্রশ্ন অনুসারে,
(PQ + PR + QR) এর মান =
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