Calculate the shape factor of a flow net having four flow channels and sixteen equipotential drops.

Question

Question

This question was previously asked in

PGCIL DT Civil 5 May 2023 Official Paper

Answer 1

Explanation:

Shape factor (Depends on boundary conditions only)

S = \(\frac{{{N_f}}}{{{N_d}}}\)

S = Shape factor

Nf = number of flow channels

Nd = number of equipotential drops

Calculation:

Given:

Nf = 4, Nd = 16

Shape factor

S = \(\frac{{{N_f}}}{{{N_d}}}\) = \({4 \over 16} = {1\over 4}\) = 0.25

Additional Information Seepage discharge is given by,

\(q = KH\frac{{{N_f}}}{{{N_d}}}\)

Where,

K = Coefficient of permeability

H = Head under which flow is taking place