Figure 1.5 shows electric field lines in which an electric dipole p is placed as shown. Which of the following statements is correct?

Question

Question

Answer 1

Explanation:

In the given figure, the electric field lines are not uniform.

→Electric field lines are stronger on the left side than on the right.

We know Force on a charged particle kept in an electric field is given as:

\(\vec{F} = q \vec{E}\)

→Therefore the force on the negative charge due to Electric field E₁ will be:

\(\vec{F_1} = -q \vec{E_1}\)

→And the force on the positive charge due to Electric field E2 will be:

\(\vec{F_2} = q \vec{E_2}\)

Since E1>E2 then F₁>F₂, and the net force on the dipole will be towards the left

Hence, the correct option is (3)

Download Solution PDF