Find the range of function sin(ex).

  1. All real number
  2. (-∞, -1] [1, ∞)
  3. [-1, 1]
  4. None of these
  5. (-∞, -1] 

Answer (Detailed Solution Below)

Option 3 : [-1, 1]
Free
BSF HC RO/RM All India Mega Live Test
5.4 K Users
100 Questions 200 Marks 120 Mins

Detailed Solution

Download Solution PDF

CONCEPT:

Exponential functions are functions of the form f(x) = bx for a fixed base b which could be any positive real number.

The inverse of an exponential function is a logarithmic function. For the exponential function y=abx–h + k:

  • The domain is all real numbers.
  • The range is {y | y>k} if a > 0 or {y | y<k} if a < 0.
  • Range of sin (x) is [-1, 1] and domain is R.
     

CALCULATIONS:

Given function is f (x) = sin(ex).

On comparing ex with y=abx–h + k, k = 0, a > 0

In this question range of ex will be the domain for sin function.

Range of ex is {y | y>0}, since k=0 and a>0.

So, range of sin(ex) will be [-1, 1]
Latest NDA Updates

Last updated on May 30, 2025

->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.

-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

Get Free Access Now
Hot Links: teen patti king teen patti baaz rummy teen patti teen patti casino apk